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kvasek [131]
2 years ago
10

What is the surface area of the cylinder? Use three and fourteen-hundredths for pi and round to the nearest hundredth. Enter you

r answer in the box. height is 11 radius is 8 use 3.14 for pi
Mathematics
1 answer:
nadya68 [22]2 years ago
3 0

Answer:

954.56 cm²

Step-by-step explanation:

Firstly i would calculate the circumference of the circles on top of the cylinders:

Circumference of circles = \pi d or 2\pi r

d = diameter

r = radius

I will use 2\pi r

circumference = 2 x 3.14 x 8 = 50.24 cm

⇒ This would help me to find out the surface area of the side of the cylinder

50.24 x 11 = 552.64 cm²

⇒ This is the surface are of the sides

Now we have to find the are of the two circles on the top and the bottom:

Area of a circle = \pi d^{2}

d = diameter

3.14 x 8² = 200.96

⇒ There are two circles so you would times 200.96 by 2

200.96 x 2 = 401.92

Add all the values up:

401.92 + 552.64 = 954.56 cm²

I hope this helps!

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A bag contains 4 white,5 blacks and 2 blue balls. 3 balls are drawn one after the other without replacement from the bag .what i
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Answer:

24/99

Step-by-step explanation:

From the question given above, the following data were obtained:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

Probability that they are of different color =?

Next, we shall determine the total number of balls in the bag. This can be obtained as follow:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 4 + 5 + 2 = 11 balls

Next, we shall determine the possible outcome of draw. This can be obtained as follow.

The possible outcome could be:

WBLB or WBBL or BBLW or BWBL or BLBW or BLWB

Next we shall determine the probability of each of outcomes.

Since the ball is drawn without replacement, it means the total number of ball will reduce after each draw.

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 11

P(WBLB) = 4/11 × 2/10 × 5/9 = 40/990

P(WBLB) = 4/99

P(WBBL) = 4/11 × 5/10 × 2/9 = 40/990

P(WBBL) = 4/99

P(BBLW) = 5/11 × 2/10 × 4/9 = 40/990

P(BBLW) = 4/99

P(BWBL) = 5/11 × 4/10 × 2/9 = 40/990

P(BWBL) = 4/99

P(BLBW) = 2/11 × 5/10 × 4/9 = 40/990

P(BLBW) = 4/99

P(BLWB) = 2/11 × 4/10 × 5/9 = 40/990

P(BLWB) = 4/99

Finally, we shall determine the probability that they are of different color. This can be obtained as follow:

P(WBLB) = 4/99

P(WBBL) = 4/99

P(BBLW) = 4/99

P(BWBL) = 4/99

P(BLBW) = 4/99

P(BLWB) = 4/99

Probability that they are of different color =?

Probability that they are of different color = P(WBLB) + P(WBBL) + P(BBLW) + P(BWBL) + P(BLBW) + P(BLWB)

= 4/99 + 4/99 + 4/99 + 4/99 + 4/99 + 4/99

= (4 + 4 + 4 + 4 + 4 + 4)/99

= 24/99

Thus, the probability that they are of different color is 24/99

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