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Yuki888 [10]
3 years ago
6

Find the area of wyz

Mathematics
1 answer:
zlopas [31]3 years ago
8 0
B. multiply the whole thing for the area then divide by two bcs its a triangle
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56.27 in expanded form​
Lana71 [14]

Answer:

Step-by-step explanation:

 56.27 =

 50  

+ 6  

+   0.2

+   0.07

Expanded Factors Form:

   56.27 =

 5 × 10  

+ 6 × 1  

+ 2 ×   0.1

+ 7 ×   0.01

Expanded Exponential Form:

 56.27 =

5 × 101

+ 6 × 100

+ 2 × 10-1

+ 7 × 10-2

Word Form:

56.27 =

fifty-six and twenty-seven hundredths

5 0
3 years ago
If 7(x-7)=-15 then x =
soldi70 [24.7K]

7(x-7)=-15

distribute

7x-49 =-15

add 49 to each side

7x =34

divide by 7

x = 34/7

x = 4 6/7

6 0
3 years ago
A. Determine the y-intercept by<br> substituting 0 for x
Sergeu [11.5K]
What’s the question?
6 0
3 years ago
Which of the following expressions is equivalent to the expression x - (-3) ?
ziro4ka [17]
D.
X+3
I attached a picture

6 0
3 years ago
Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points. Rachel scored 78 p
Artemon [7]

Answer:

Keenan's z-score was of 0.61.

Rachel's z-score was of 0.81.

Step-by-step explanation:

Z-score:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.

This means that X = 80, \mu = 77, \sigma = 4.9

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{80 - 77}{4.9}

Z = 0.61

Keenan's z-score was of 0.61.

Rachel scored 78 points on an exam that had a mean score of 75 points and a standard deviation of 3.7 points.

This means that X = 78, \mu = 75, \sigma = 3.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{75 - 78}{3.7}

Z = 0.81

Rachel's z-score was of 0.81.

6 0
3 years ago
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