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PSYCHO15rus [73]
2 years ago
8

3. Triangle JKL is shown below. Which of the following is not a true statement about

Mathematics
1 answer:
alina1380 [7]2 years ago
4 0

Option A is true because the sum of angles in a triangle is 180, so we can rule that one out immediately.

We can solve for x for the other 3 options by setting up this equation:

7x+2 + 4x+7 + 8x = 180 | Simplify

19x + 9 = 180 | Subtract 9

19x = 171 | Divide by 19
x=9

Now we can substitute x into all the values:
<J = 7x+2 = 65
<L = 4x+7 = 43
<K = 8x = 72


Looking at the options again, we can see that A, B, and D are true, leaving C to be false.

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7 1/4 times 2 x 2 + (8 1/2 - 2) divided by 3
11111nata11111 [884]
The answer is 31 1/6, I hope this helps!
6 0
3 years ago
Find the solutions to the equation below.<br> Check all that apply.<br> x2 - 4 = 0
Gennadij [26K]

Answer:

2

Step-by-step explanation:

First you add 4 to both sides and get

2x=4

then you divide by 2 and get

4/2=x

4/2=2

x=2

8 0
3 years ago
Read 2 more answers
What is the answer to this question
julia-pushkina [17]
I hope this helps you



Formula => I=PRT


900=7500.R.2


R=900/15000


R=0,06



3 0
3 years ago
A study was conducted to determine the mean birth weight of a certain breed of kittens. Consider the birth weights of kittens to
Scrat [10]
1) Call x the sample mean = 3.56

2) Call s the sample standard deviation = 0.2

3) Given that the variable is normally distributed and the sample is large, you determine the interval of confidence from:

x +/- Z(0.5) s/√n

Wehre Z(0.5) is the value of the probabilities over 5% (90% of confidence mean to subtract 10%, which is 5% for each side (tails) of the normal distribuition) and is taken from tables.

Z(0.5) = 0.3085

Then the inteval is

x +/- 0.385 *s /√n = 3.56 +/- 0.385 * 0.2/√45

3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.
8 0
4 years ago
Running times for 400 meters are Normally distributed for young men between 18 and 30 years of age with a mean of 93 seconds and
kkurt [141]

Answer: The running time should at least 119.32 seconds to be in the top 5% of runners.

Step-by-step explanation:

Let X= random variable that represents the running time of men between 18 and 30 years of age.

As per given, X is normally distrusted with mean \mu=93\text{ seconds} and standard deviation \sigma=16\text{ seconds}.

To find: x in top 5% i.e. we need to find x such that P(X<x)=95% or 0.95.

i.e. P(\dfrac{X-\mu}{\sigma}

P(Z

Since, z-value for 0.95 p-value ( one-tailed) =1.645

So,

Hence, the running time should at least 119.32 seconds to be in the top 5% of runners.

6 0
3 years ago
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