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Inessa05 [86]
3 years ago
12

Farmer brown likes to grow his crops in equal amounts if the carrot seeds come in packs of 80 the zunchie come in packs of 40 an

d the paper in packs of 50 what is the fewest number of each kind of seed that farmer brown will by
Mathematics
1 answer:
solniwko [45]3 years ago
4 0

Given,

The carrot comes in pack of 80

Zunchie comes in the pack of 40

The paper comes in the pack of 50.

To find,

The fewest number of each kind of seed that farmer brown will buy.

Solution,

To find least no of each kind, we must take the LCM of the above numbers such that,

The prime factors of the given numbers are :

80 = 2 × 2 × 2 × 2 × 5

40 = 2 × 2 × 2 × 5

50 = 2 × 5 × 5

LCM of 80,40 and 50 = 2 × 2 × 2 × 2 × 5 × 5

= 400

He should buy,

400/80 = 5 carrot seeds

400/40 = 10 zunchie seeds

400/50 = 8 papper seeds.

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Answer:

(-3, 13)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  4. Multiplication
  5. Division
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  • Addition Property of Equality
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y = -4x + 1

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<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                                                                                                  11(-4x + 1) = x + 146
  2. Distribute 11:                                                                                                      -44x + 11 = x + 146
  3. [Addition Property of Equality] Add 44x on both sides:                                11 = 45x + 146
  4. [Subtraction Property of Equality] Subtract 146 on both sides:                      -135 = 45x
  5. [Division Property of Equality] Divide 45 on both sides:                              -3 = x
  6. Rewrite/Rearrange:                                                                                          x = -3

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                                                                                 y = -4x + 1
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