All categories

2 years ago

How many WATTS are used in a 5 amp drill that uses 110 volts?

1 answer:

8 0

Calculating wattage is a quick process once you know the appliance's amperage and voltage — you simply multiply the two figures. An appliance that uses 110 volts of electricity and 5 amps uses 550 watts.

Hope this helps!

You might be interested in

Please help me with number 22 and if you can part b to please

m_a_m_a [10]

It's not a good picture.it's not possible to read it

6 0

3 years ago

a set v is given, together with definitions of addition and scalar multiplication. determine which properties of a vector space

agasfer [191]

The properties of a vector space are satisfied Properties 1,2, 5(a) and 5(c) are satisfied, the relaxation of the homes aren't legitimate are if $v = x ^ 2 1× v=1^ ×x ^ 2 = 1 #V$

Property three does now no longer follow: Suppose that Property three is legitimate, shall we name $v = a * x ^ 2 +bx +c$ the neuter of V. Since v is the neuter, then O have to be constant with the aid of using the neuted, consequently $0 = O + v = (O x ^ 2 + Ox + O) + (a × x ^ 2 + bx + c) = c × x ^ 2 + b ^ 2 + a$

= 0 If O is the neuter, then it ought to restore x², but $0+ x² = (0x²+0x+zero) + (x²+0x+zero) = 1.$ This is a contradiction due to the fact x² isn't 1. We finish that V doesnt have a neuter vector. This additionally method that belongings four would not observe either. A set with out 0 cant

have additive inverse

$Let r= v ×2x ^ 2 + v × 1x +v0 , w= w ×2x ^ 2 + w × 1x +w0 . We have that\\v+w= (vO + wO) ^ x^ 2 +(vl^ × wl)^ x+ ( v 2^ × w2)• w+v= (wO + vO) ^x^ 2 +(wl^ × vl)x+ ( w 2^ ×v2)$

Since the sum of actual numbers is commutative, we finish that v + w = w + v Therefore, belongings 5(a) is valid.

Property 5(b) isn't valid: we are able to introduce

a counter example. we could use z = 1 then $v = x ^ 2 w = x ^ 2 + 1\\(v + w) + z = (x ^ 2 + 2) + 1 = 3x ^ 2 + 1$

v + (w + z) = x ^ 2 + (2x ^ 2 + 1) = x ^ 2 + 3

Since 3x ^ 2 +1 ne x^ 2 +3. then the associativity rule doesnt hold.

$(1+2)^ * (x^ 2 +x)=3^ * (x ^ 2 + x) = 3x + 3\\1^ × (x^ 2 +x)+2^ × (x ^ 2 + x) = (x + 1) + (2x + 2) = 3x ^ 2 + x ( ne 3x + 3 )\\(1^ ×2)^ ×(x^ 2 +x)=2^ × (x ^ 2 + x) = 2x + 2\\1^ × (2^ × (x ^ 2 + x) )=1^ × (2x+2)=2x^ 2 +2x( ne2x+2)$

Property f doesnt observe because of the switch of variables. for instance, if v = x ^ 2 1 × v=1^ × x ^ 2 = 1 #V

Properties 1,2, 5(a) and 5(c) are satisfied, the relaxation of the homes arent legitimate.

Step-with the aid of using-step explanation:

Note that each sum and scalar multiplication entails in replacing the order from that most important coefficient with the impartial time period earlier than doing the same old sum/scalar multiplication.

Property three does now no longer follow: Suppose that Property three is legitimate, shall we name v = a × x ^ 2 +bx +c the neuter of V. Since v is the neuter, then O have to be constant with the aid of using the neuted, consequently $0 = O + v = (O × x ^ 2 + Ox + O) + (a × x ^ 2 + bx + c) = c × x ^ 2 + b ^ 2 + a$

= zero If O is the neuter, then it ought to restore x², but zero $+ x² = (0x²+0x+zero) + (x²+0x+zero) = 1.$ This is a contradiction due to the fact x² isn't 1. We finish that V doesnt have a neuter vector. This additionally method that belongings four would not observe either. A set with out 0 cant have additive inverse

Let $r= v × 2x ^ 2 + v × 1x +v0 , w= w2x ^ 2 + w × 1x +w0 . \\We have thatv+w= (vO + wO) ^ x^ 2 +(vl^ wl)^x+ ( v 2^ w2)w+v= (wO + vO) ^ x^ 2 +(wl^ vl)x+ ( w 2^v2)$

Since the sum of actual numbers is commutative, we finish that v + w = w + v Therefore, belongings 5(a) is valid.

Property 5(b) isn't valid: we are able to introduce

a counter example. we could use $z = 1 then v = x ^ 2 w = x ^ 2 + 1(v + w) + z = (x ^ 2 + 2) + 1 = 3x ^ 2 + 1v + (w + z) = x ^ 2 + (2x ^ 2 + 1) = x ^ 2 + 3\\Since 3x ^ 2 +1 ne x^ 2 +3.$ then the associativity rule doesnt hold.

Note that each expressions are same because of the distributive rule of actual numbers. Also, you could be aware that his assets holds due to the fact in each instances we 'switch variables twice.

$· (1+2)^ * (x^ 2 +x)=3^ * (x ^ 2 + x) = 3x + 31^ * (x^ 2 +x)+2^ * (x ^ 2 + x) = (x + 1) + (2x + 2) = 3x ^ 2 + x ( ne 3x + 3 )(1^ * 2)^ * (x^ 2 +x)=2^ * (x ^ 2 + x) = 2x + 21^ * (2^ * (x ^ 2 + x) )=1^ ×* (2x+2)=2x^ 2 +2x( ne2x+2)$

Read more about polynomials :

brainly.com/question/2833285

#SPJ4

8 0

1 year ago

Help! Can anyone help? I’ve been stuck.. I’ll make sure to give Brainly. The answer is not 3,850. Thank you.

erik [133]

9514 1404 393

Answer:

$3400

Step-by-step explanation:

The way these tax tables are structured, you pay 3% on the first $10,000, 5% on the next $40,000, and 5.5% on the remaining $20,000 above $50,000.

tax = 0.03·10,000 +0.05·(50,000 -10,000) +0.055·(70,000 -50000)

= 300 + 2000 +1100

= 3400 . . . dollars

The tax owed on $70,000 is $3,400.

_____

<em>Additional comment</em>

I like to rewrite this sort of table to a different format:

3% of income . . . . . . . . . . . . . . . applies for income ≤ 10,000
(5% of income) -$200 . . . . . . . . applies for 10,000 < income ≤ 50,000
(5.5% of income) -$450 . . . . . . .applies for 50,000 < income ≤ 100,000

For an income of $70,000, the tax computation using this form is one multiplication and one addition, rather than 3 multiplications and 4 additions as used when navigating the given table.

6 0

3 years ago

The sum of two numbers is 95. If the larger is increased by twice the smaller, the result is 120. Find the numbers.

adelina 88 [10]

Hello!

You can make two expressions based on what you know

let x equal the larger number
let y equal the smaller number

x + y = 95
x + 2y = 120

We can use elimination to get rid of x

You can subtract the two equation to get rid of x

-y = -25

Since y is negative we can multiply both sides by -1 to make y positive

y = 25

Now we can put this into one of the other equations to find x

x + 25 = 95

subtract 95 from both sides

x = 70

The answers are 70 and 25

Hope this helps!

3 0

3 years ago

I need help it's due by 7

devlian [24]

Answer:

Step-by-step explanation:

w=204.8

3 0

3 years ago

Read 2 more answers