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Vinvika [58]
3 years ago
5

A photographer is planning to enlarge a photograph by a scale factor of 1:5 . The original photograph has an area of 154 square

inches.
What is the area of the new photograph?

_____in²
Mathematics
2 answers:
Step2247 [10]3 years ago
8 0
Your answer should have been 3850 in^2 

1^2/5^2 = 1/25

1/25 = 154/x
1x= 154 (25)
1x/1= 3850/1
x= 3850
tankabanditka [31]3 years ago
7 0

A photographer is planning to enlarge a photograph by a scale factor of 1:5 . The original photograph has an area of 154 square inches.

Solution:

The photograph is being enlarged by a factor 5.

So, each dimension of the photograph is enlarged by 5

So, area is enlarged by 5^{2}

Or, Area is enlarged by a factor=5*5=25

So, the Area of enlarged photograph=5^{2} *Area of original photograph

Area of enlarged photograph=25*Area of original photograph

Area of enlarged photograph=25*154

On multiplying 25 by 154 we get 3850

Area of enlarged photograph=3850inches^{2}

Answer:

Area of new photograph=3850in^{2}

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p=1/2pi*r

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28.56=3.14*r

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Answer:

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b) The average value of the sinusoidal function for daylight hours is given as 12 hours, 8 minutes, about 12.133 hours. The amplitude of the function is given as 2 hours 53 minutes, about 2.883 hours. Without too much error, we can assume the year length is 365.25 days, so that is the period of the function,

March 21 is day 80 of the year, so that will be the horizontal offset of the function. Putting these values into the form ...

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explanation: add all of them up and divid by how many numbers are in the data set
74+81+77+88=320
then divid 320 by 4 =160




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