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Hoochie [10]
2 years ago
12

Bob has 150 grams of gold, and he wants to use it all to make a cube. Given that the density of gold is 19.3 grams / cubic centi

meter, how long should each side of the cube be? (Round your answer to the nearest hundredth.) Show all work/Explanation
Mathematics
1 answer:
Mice21 [21]2 years ago
4 0

Answer:

1.98 cm side length of the cube

Step-by-step explanation:

150 gm / 19.3 gm/cm^3 = 7.77202 cm^3

  take the cube root to find the side length = 1.98 cm

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Solve for 3/4u = 12<br> .<br> Simplify your answer as much as possible.
Wittaler [7]

Answer:

u = 16

Step-by-step explanation:

Given

\frac{3}{4} u = 12

Multiply both sides by 4 to eliminate the fraction

3u = 48 ( divide both sides by 3 )

u = 16

6 0
3 years ago
Explain how to find which is greater 1/4 of 12 or 1/3 of 12
stiks02 [169]
1/3 would be greater because 
1/3 of 12= 4 while 
1/4 of 12 = 3
to check your work you would get a calculator (if possible) and divide 3by 12 or 4 by 12 then if you get .33 (divide 3 by 12 like 3/12) its 1/3. if its .25 (divide 4 by 12 like 4/12) its 1/4
4 0
3 years ago
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31 cups are = to how many gallons ​
Pavel [41]

The answer is 1.9 gallons

6 0
3 years ago
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There are 10 true-false questions and 20 multiple choice questions from which to choose a five-question quiz how many ways can t
beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

3 0
3 years ago
Which is the next term in the pattern 1/12, 4/15, 9/18, 16/21
Amiraneli [1.4K]
25/24 is the answer.
3 0
3 years ago
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