<span>given:
bull's eye radius= x
width of surrounding rings=y
solution:
Radius of the circle=x+4y
Area of the outermost ring=Area of the circle-Area of the penultimate ring
=Ď€(x+4y)^2-Ď€(x+3y)^2
=Ď€(x^2+8xy+16y^2-x^2-9y^2-6xy)
=Ď€(2xy+7y^2)
hence the area of the outermost ring in terms of x and y is π(2xy+7y^2).</span>
Answer:
D
Step-by-step explanation:
i added it
Answer:
(y - 4)(y + 4)
Step-by-step explanation:
y² - 16 ← is a difference of squares
Since y² and 16 are both squares separated by a difference , that is minus
A difference of squares factors as
y² - 16
= y² - 4²
= (y - 4)(y + 4)
X-9=12
x-9+9=12+9
You need to add 9 to each side of the equation.
x=21
No, the answer is 3/8 because if 3/4 of the cars are Sudan's, and half of that three quarters are white, you need to divide three quarters into two to get the answer. I did this question by using the equivalent fraction 6/8 and dividing both numbers into two.
