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grandymaker [24]
2 years ago
15

Point A is 4 units away from the origin along the x-axis, and is 7 units away along the y-axis. Which of the following could be

the coordinates of Point A?
A. (7, 4)

B. (4, 11)

C. (4, 7)

D. (11, 4)
Mathematics
2 answers:
siniylev [52]2 years ago
6 0
Answer: C (4,7)

Points are labeled as (x,y)

If the unknown point is 4 units away from the origin on the x axis, x will be 4

If the unknown point is 7 units away from the origin on the y axis, y will be 7

Therefore (4,7)
Sedaia [141]2 years ago
5 0
C.
because the x axis is always first of coronates and the y axis is second
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Answer:

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Step-by-step explanation:

2(x+4) - 10 =14

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simplify                     2x-2=14

add 2                        2x=16

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Determine if -8T- 20 = 4(-2T -5) has one solution, infinitely many solutions, or no solution
AnnZ [28]

Answer:

infinitely many solutions

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-8T- 20 = 4(-2T -5)

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-8T- 20 = (-8T -20)

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3 years ago
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The area of a rectangle is 56 cm. the length is 2 less than x and the width is 5 less than twice of x. solve for x
Nostrana [21]

Answer:

x=\frac{9+\sqrt{449}}{4}

Step-by-step explanation:

The area of a rectangle is:

A=l\cdot w

First let's write both the length and the width in terms of x:

l=x-2

<u>How we obtained the answer</u>:

The question states the length is "2 less than x". In this case, "less" is a keyword that represents subtraction. Therefore, "2 less than x" is "x-2".

w=2x-5

<u>How we obtained the answer</u>:

The question states the width is "5 less than twice of x". First, start by figuring out what "twice of x" is. The keyword is "twice" which represents multiplication. Therefore, "twice of x" can be written as "2x". Then, using the same keyword from before ("less"), "5 less than..." represents "2x-5".

Given:

Area = 56 cm

l=x-2

w=2x-5

Find:

x

A=l\cdot w

56=(x-2)(2x-5)

FOIL (Firsts, outsides, insides, lasts):

56=2x^2-4x-5x+10\\56=2x^2-9x+10

Subtract 10 from both sides:

46=2x^2-9x

Subtract 46 from both sides (forms a quadratic equation):

0=2x^2-9x-46

Use the quadratic formula:

{x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}  where 0=ax^2+bx+c

Therefore:

x=\frac{9\pm\sqrt{81-4(2)(-46)}}{2(2)}\\x=\frac{9\pm\sqrt{81+368}}{4}\\\\x=\frac{9\pm\sqrt{449}}{4}

The answer is:

x=\frac{9+\sqrt{449}}{4}

This is because if we used subtraction, we would get a negative value, and we cannot have a negative length/width.

4 0
2 years ago
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