I'll do the first two to get you started
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Problem 1
A = 3 = starting value
B = 10 = ending value
C = percent change
C = [ (B - A)/A ] * 100%
C = [ (10-3)/3 ] * 100%
C = (7/3) * 100%
C = 2.3333333 * 100%
C = 233.33333%
C = 233.3%
The positive C value means we have a percent increase. If C was negative, then we'd have a percent decrease.
<h3>Answer: 233.3% increase</h3>
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Problem 2
A = 9 = start value
B = 20 = end value
C = percent change
C = [ (B - A)/A ] * 100%
C = [ (20-9)/9 ] * 100%
C = (11/9)*100%
C = 1.2222222222*100%
C = 122.22222222%
C = 122.2%
<h3>Answer: 122.2% increase</h3>
Answer:
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Answer:
32
Step-by-step explanation:
From the given values
The possible logic could be
if x.y is given
then it is equal to
For 1st example
3.4
For 2nd example
2.5
⇒4.4
P(more than 1 hour of TV | 6th period class) is 0.352.
<h3>What is the probability?</h3>
Probability determines the odds that a random event would happen. The odds of the random event happening lie between 0 and 1.
P(more than 1 hour of TV | 6th period class) = number of 6th period class students who watch tv for more than an hour / total number of students surveyed
12 / (12 + 9 + 5 + 8)
12 / 34 = 0.352
To learn more about probability, please check: brainly.com/question/13234031
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