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tangare [24]
1 year ago
11

Identify the coordinates of four points on the line with each given slope and y-intercept. slope = 2/3 and y-intercept = -5

Mathematics
1 answer:
fredd [130]1 year ago
6 0

The coordinates of four points on the line are (0,-5), (3,-3), (6,-1) and (9,1)

<h3>How to determine the coordinates?</h3>

The given parameters are given as:

  • Slope, m = 2/3
  • y-intercept, c = -5

The equation is represented as:

y = mx + c

So, we have:

y = 2/3x -5

When x = 0, we have;

y = 2/3 * 0 -5 = -5

When x = 3, we have;

y = 2/3 * 3 -5 = -3

When x = 6, we have;

y = 2/3 * 6 -5 = -1

When x = 9, we have;

y = 2/3 * 9 -5 = 1

Hence, the coordinates of four points on the line are (0,-5), (3,-3), (6,-1) and (9,1)

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

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Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34

Step-by-step explanation:

Given:

2x-3y=12

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

2x-3y=12  

Solution:

2x-3y=12 ...........Given

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Comparing with,  

y=mx

Where m =slope  

We get

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We know that for Perpendicular lines have product slopes = -1.

m1\times m2=-1

Substituting m1 we get m2 as

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Therefore the slope of the required line passing through (16 , -7) will have the slope,

m2=-\dfrac{3}{2}

Now the equation of line in slope point form given by

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Substituting the point (16 , -7)  and slope m2 we will get the required equation of the line,

(y-7)=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34

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The value of a professor basketball players autograph rose 30% in the las year.It is now worth $286.00. What was it worth a year
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