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3 years ago

(–5.7 • 2) • 8 = –5.7 • (2 • x)

Mathematics

2 answers:

aivan3 [116]3 years ago

8 0

(-11.4) · 8 = -5.7 · (2 · x)
-91.2 = -5.7 · (2 · x)
16 = 2 · x
x = 8

pashok25 [27]3 years ago

7 0

It's 8 because of the commutative property.

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likoan [24]

Answer:

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Step-by-step explanation:

$A=6*\frac{1}{4} ^2\\\\A=6*\frac{1}{16} \\\\A=\frac{6}{16} \\\\A=\frac{3}{8}$

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1 year ago

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3 years ago

What is the value of "c" in the following quadratic? (Make sure the equation is in

garri49 [273]

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}\rule{50}{1}$

<em>What is the value of c in the quadratic </em> $\large\text{$x^2+28=-11x$}$ ?

$\rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

Before starting to solve, you should notice something - the

quadratic is not in its standard form!

We can easily fix it by adding $\large\textit{11x}$ on both sides:-

$\large\text{$x^2+28-11x=0$}$

We can switch the order of 28 and -11x:-

$\large\text{$x^2-11x+28=0$}$

Now, the quadratic is in its standard form, so we can get down to

finding the value of "c".

Remember, the standard form of a quadratic looks like so:-

$\large\text{$ax^2+bx+c=0$}$

Now we can just write our <u>quadratic</u> here:-

$\large\text{$x^2-11x+28=0$}$

Now, can you see what the value of "c" is?

An easy way to <u>remember</u> "c" in quadratics is:-

The "c" in quadratics is the constant.

Henceforth, we conclude that the value of "c" in the given quadratic is:-

$\Large\textbf{28}\Large\checkmark$

<h3> Good luck with your studies.</h3>

$\rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}$

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