We know that , in a circle radius perpendicular to chord will bisect the chord.
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Answer:
k=21
Step-by-step explanation:
Find the slope of MN which is 1/5 (use the slope formula)
Use the slope formula for AB using k as y_2
Substitute and you get k=21
21-2.25/-2.25-1.5=-5
The lines are perpendicular because the slopes are the negative reciprocal of one another.
-1+1=0. So your answer is -1 and 1
Answer:
480 students
Step-by-step explanation:
600 x .80
