1. Different ideas from different scientists (such as schleiden and schwann)
2. B. Describe and examine cells
3. Sorry i don't remember this
hope this helps :)
Answer:
0.16 atm
Explanation:
Let's look at the formula PV=nRT. First of all, T should be in kelvin, so let's add 273. Now solve for P so we get P = nRT/V.
Now let's plug these in...
P = (0.034 mol)(0.08206 L atm mol^-1 K^-1)(298 K)/5.1 L
After solving and rounding to sig figs we get 0.16 atm
The pH meter can only be used to differentiate between weak and strong acids providing that the concentrations are known. However, it is convenient to determine the concentration of an acid (or base) by titration.
Answer:
Average atomic mass of uranium = 237.97 amu
Explanation:
Given data:
Abundance of U-234 = 0.01%
Abundance of U-235 = 0.71%
Abundance of U-238 = 99.28%
Average atomic mass of uranium = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100
Average atomic mass = (234×0.01)+(235×0.71)+(238+99.28) /100
Average atomic mass = 2.34 + 166.85+23628.64 / 100
Average atomic mass = 23797.83 / 100
Average atomic mass = 237.97 amu.
