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kap26 [50]
1 year ago
8

Simplify the radical expression -√5q^3*3√35

Mathematics
1 answer:
andre [41]1 year ago
6 0

-\sqrt{5q^3} \cdot 3\sqrt{35}\\\\=-3\sqrt{5}\cdot \sqrt{q^3} \cdot  \sqrt{5 \cdot 7}\\\\=-3\sqrt 5\cdot \sqrt{q \cdot q^2} \cdot \sqrt{5} \cdot \sqrt 7\\\\=-3\left(\sqrt 5 \right)^2 \cdot q\sqrt q \cdot \sqrt 7\\\\=-3\cdot 5 \cdot q\sqrt{7q}\\\\=-15q\sqrt{7q}

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yra solves the equation as shown. - 3(x+2) = 9 1. - 3x - 6 = 9 2. - 3x = 15 3. x = - 5 The property Tyra used in line 1 was the:
Molodets [167]

Answer:

Distributive property says that:

a\cdot(b+c) = a\cdot b + a\cdot c

Addition property of equality:

if x = y then x+z = y+z

Division property of equality:

if x = y then \frac{x}{z}=\frac{y}{z}

As per the statement:

Given the equation: -3(x+2)=9

Tyra solve this equation as shown below:

1.

-3x -6 = 9               [Distributive property]

2.

-3x = 15                 [Addition property of equality]

3.

x = -5                    {Division property of equality]

Therefore, the  property Tyra used in line 1 was : Distributive Property.

5 0
2 years ago
Read 2 more answers
Q = 15<br> a = 16<br> What would you do with q and a to get 240?
ch4aika [34]

You multiply Q and a to get 240, because 15 x 16 = 240.

6 0
3 years ago
Select the measures of the angles of a triangle whose angles have measures in the ratio 6:8:10
morpeh [17]

Answer:

45, 60, 75

Step-by-step explanation:

The ratio of the angles are 6:8:10

Multiply by x to get the angle measures

6x, 8x,10x

We know the sum of the angles is 180 for a triangle

6x+8x+10x = 180

Combine like terms

24x = 180

Divide each side by 24

24x/24 = 180/24

x =7.5

Each angle is

6x = 6(7.5) =45

8x = 8(7.5) =60

10x = 10*7.5 = 75

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3 years ago
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bulgar [2K]

Answer:

Step-by-step explanation:

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2 years ago
What is the value of (7 + 2i)(3 - i)?
Harrizon [31]
There are two ways to work this out: normal variables or using "imaginary" numbers.

Normal variables:
(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}

Imaginary numbers:
Using the result from earlier:
21-i-2i^{2}
Now since i = \sqrt{-1}, then the expression becomes:
21-i-2i^{2}\\21-i-2(\sqrt{-1})^{2}\\21-i+(-2)(-1)\\21-i+2\\\\23-i
7 0
3 years ago
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