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2 years ago

A sketch of Jessie's neighborhood is shown below. Which equation can Jessie use to determine x, the distance from

Mathematics

1 answer:

lana66690 [7]2 years ago

5 0

Answer:

the equation that determines the length of the base, sorry i forgot the name of it

Step-by-step explanation:

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A theater has 28 rows of 38 seats downstairs and 14 rows of 26 seats upstairs.How many seats does the theater have?

Triss [41]

For downstairs- 28 x 38= 1064

For upstairs- 26 x 14= 364

All together- 1064 + 364= 1428

So.... 1428 seats in total.

Hope this helped! :)

3 0

2 years ago

A pair of events are observed to have coordinates (0s,0m) and (50.0s,9.00×109m) in a frame s. what is the proper time interval δ

Ludmilka [50]

To find out time interval δt we need to substract initial time from the final time. In this question first number in the coordinates representes time:

δt=50 - 0
δt= 50s

TIme interval is 50s.

5 0

2 years ago

Wanda needs to buy packages of colored paper. Each package contains 320 pieces of paper. If she buys 18 packages, how many piece

Vsevolod [243]

Answer:

18 x 320=5,760 pieces of paper

Step-by-step explanation:

5,760

3 0

2 years ago

Rotate the axes to eliminate the xy-term in the equation. Then write the equation in standard form.

kirill115 [55]

Answer:

$\dfrac{x'^2}{2}-\dfrac{y'^2}{2}=1$

Step-by-step explanation:

The rotation by angle $\theta$ formulas are

$\left\{\begin{array}{l}x=x'\cos \theta-y'\sin \theta\\y=x'\sin \theta+y' \cos \theta\end{array} \right.$

To eliminate the xy-term, we have to rotate by 45°, so

$\left\{\begin{array}{l}x=x'\cos 45^{\circ}-y'\sin 45^{\circ}\\y=x'\sin 45^{\circ} +y' \cos 45^{\circ}\end{array} \right.$

$\left\{\begin{array}{l}x=x'\dfrac{\sqrt{2}}{2}-y'\dfrac{\sqrt{2}}{2}\\y=x'\dfrac{\sqrt{2}}{2} +y' \dfrac{\sqrt{2}}{2}\end{array} \right.$

Substitute them into the equation $xy+1=0:$

$\left(x'\dfrac{\sqrt{2}}{2}-y'\dfrac{\sqrt{2}}{2}\right)\cdot \left(x'\dfrac{\sqrt{2}}{2}+y'\dfrac{\sqrt{2}}{2}\right)+1=0\\ \\\left(x'\dfrac{\sqrt{2}}{2}\right)^2 -\left(y'\dfrac{\sqrt{2}}{2}\right)^2+1=0\\ \\\dfrac{x'^2}{2}-\dfrac{y'^2}{2}=1$

8 0

2 years ago

(Select all that Apply)

Mila [183]

B: 6 + 5 = 11

six plus five does equal 11 and an EQUAtion needs to EQUAL :) ❤️

4 0

2 years ago

Read 2 more answers