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wariber [46]
4 years ago
15

PLEASE SHOW THE STEPS TAKEN TO GET TO -10 AS THE ANSWER! WILL GIVE BRAINLIEST!

Mathematics
2 answers:
olga_2 [115]4 years ago
8 0

f(x)=3x^2+2x-5

The first step is to plug in -1 as x

f(x)=3(-1)^2+2(-1)-5

Now following order of operations, we start with the ² and do multiplication

because (-1)² = 1 f(x)=3(1)+2(-1)-5

Multiply out the 1 and -1 f(x)=-3-2-5

Finally, add them together to get -10

kati45 [8]4 years ago
8 0

I used a calculator but I hoped this helped!!

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HEYYYY plz help need both parts :)
Svetach [21]
It is A and D because as you can see it is using subtraction and multiplication and I’m sorry if I am wrong I can’t see much
7 0
3 years ago
Find the root of 5x-2=0<br>x=?​
maksim [4K]

Answer: 4

Step-by-step explanation:

If you multiply 5x-2 you will get -10

Do all the steps and you get 4

Therefore your answer is 4.

5 0
3 years ago
Read 2 more answers
SOLVE IT PLEASE + do math!!!<br> |4x-3| -5=4
valentina_108 [34]
Well first add 5 to both sides
4x-3=9
then add 3 to both sides
4x=12
then divide 4 by both sides.
x=3
5 0
3 years ago
Read 2 more answers
Given: &lt;SPT = &lt;RQT, ST = RT Prove: PR = QS​
andrey2020 [161]

Answer:

See explanation

Step-by-step explanation:

Consider triangles PTS and QTR. In these triangles,

  • ST=RT - given;
  • \angle SPT=\angle RQT - given;
  • \angle STP=\angle RTQ - as vertical angles when lines PR and SQ intersect.

Thus, \triangle PTS\cong \triangle QTR by AAS postulate.

Congruent triangles have congruent corresponding sides, so

PT=QT

Consider segments PR and QS:

PR=PT+TR\ [\text{Segment addition postulate}]\\ \\QS=QT+TS\ [\text{Segment addition postulate}]\\ \\PT=QT\ [\text{Proven}]\\ \\ST=RT\ [\text{Given}]

So,

PR=SQ\ [\text{Substitution property}]

7 0
3 years ago
Middle school algebra 1
zhuklara [117]

HOW IS THIS MIDDLE SCHOOL ALGEBRA 1!??? I'm a senior in highschool and i have NEVER seen smthg THIS difficult for a middle schooler...

6 0
3 years ago
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