Answer:Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Step-by-step explanation:
Omg thx for the points ;)
Answer:
idk
Step-by-step explanation:
It looks like Brenda did since Michael forgot to take out the parenthesis<span />
B. Y = <span>|x| - 2
when moving left or right...meaning moving horizontally.......the number is added inside the parenthesis.
This one is moving up or down ....meaning moving horizontally........so the number is added outside the parenthesis. If it moves up then add(+)..........if it moves down then subtract(-). The formula used for horizontal shifts is, y=lXl + k
.Here k will become negative or remain positive based on the given data.
Now,
It's a horizontal shift, so we can eliminate C and D.
It moves down so we will subtract and therefore we can eliminate A
so the answer is B.
lets check our answer by using the formula
Y = lxl + k
moves 2 units down so our k = (-2)
Y = lxl + (-2) [substitute k]
Y = lxl - 2
</span>
