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2 years ago

Which equation represents a line which is parallel to the line y=8/7x-6?

Mathematics

1 answer:

Helga [31]2 years ago

3 0

Answer: 8x-7y = 56

Step-by-step explanation:

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Order these numbers from least to greatest, 749,340;740,999; 740,256

Sindrei [870]

256, 340, 740, 749, 749, 999,

6 0

3 years ago

Please answer this I need it aswerd

dsp73

It might either be a right triangle or a cute triangle

6 0

3 years ago

Read 2 more answers

A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat

konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles

First, we need to find b:

$a^{2} + b^{2} = h^{2}$ (1)

$b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles$

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

$\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})$

$2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:

$0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}$

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

$\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h$

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0

2 years ago

Calculate the density of the object using the information in the picture. Question 5 options: 0.052 ml/g 19.2 g/ml 19.2 ml/g 139

olga_2 [115]

The density of an object is obtained by taking the ratio of the mass of the object and its volume ; $Density = \frac{Mass}{Volume}$

There is no picture attached and no picture corresponding to the question could be found.

However, the required formular for calculating the density of an object is :

$Density = \frac{Mass}{Volume}$

The mass of the object is measured in gram(g) or kilogram(kg)

The volume of the object measured in Litre or any equivalent unit.

Therefore, the density of the object is the ratio of its mass and volume.

Learn more :brainly.com/question/24386693?referrer=searchResults

8 0

2 years ago

42,000 as a multipul of a power of 10

MrRa [10]

Answer:

$4.2 \times {10}^{4}$

Step-by-step explanation:

$42000 = 4.2000 \times \times {10}^{4} \\ = 4.2 \times {10}^{4}$

3 0

2 years ago