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Kruka [31]
3 years ago
10

for her cell phone plan ,Heather pays $30 per month plus $0.05 per text.She wants to keep her bill under $60 per month.Which ine

quality represents the number of texts, t ,Heather can send each month while staying within her budget
Mathematics
1 answer:
Vikentia [17]3 years ago
3 0
60=30+0.05t
-30 -30
--------------------
30=0.05t
--- ------
0.05 0.05
-----------------
600=t
600 texts


HOPE THIS HELPS
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Lorenzo ate 25 of his bag of almonds. His 4 friends ate equal shares of the remaining bag of almonds. Which expression represent
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Answer:

(x - 25) / 4

Step-by-step explanation:

In this scenario, we have one unknown variable which is the total of the bag of almonds, therefore we can represent this with the variable x. Since Lorenzo ate 25 of this bag we would need to subtract this from the total of the bag. Then we need to divide the remainder by 4 since each of his friends ate the rest in equal parts. This would leave us with the following expression ...

(x - 25) / 4

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Can someone plz help me with this!
asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

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System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

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System #2: x=1

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Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

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System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

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System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

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<em>no solution</em>

System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

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