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marin [14]
3 years ago
14

Find the solution of this system of equations x - 4y = 31, -x + 3y = -25

Mathematics
1 answer:
Viktor [21]3 years ago
4 0
This is the solution

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Angle A and angle B are vertical anglesIf m angle A=(5x-3)^ and m angle B=(4x+21)^ then find the measure of angle A .
taurus [48]

Answer:

78

Step-by-step explanation:

5x3+4+21=78

7 0
3 years ago
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State one similarity and two differences between quadratic and absolute value graphs.
Oksi-84 [34.3K]

Answer:

Linear functions are graphed as straight lines because the x variable is not raised to any exponent. They are like the flat bridge. Quadratic functions are typically in the form y = ax2 + bx + c. Quadratic functions will always have the x variable to the second power.

Step-by-step explanation:

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4 years ago
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A computer program used to organize numerical data in table format is called a___
astraxan [27]

Answer:

The answer is spreadsheet

7 0
3 years ago
Suppose you observe a data point x = 12 and it is known that this data point came from a normal distribution with mean 5 and sta
mihalych1998 [28]

Answer:

The observation would be considered unusual because it is farther than three standard deviations from the mean.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When Z has an absolute value higher than 2, the observation is considered unusual.

In this problem, we have that:

\mu = 5, \sigma = 2, X = 12

Z = \frac{X - \mu}{\sigma}

Z = \frac{12 - 5}{2}

Z = 3.5

So the correct answer is:

The observation would be considered unusual because it is farther than three standard deviations from the mean.

3 0
4 years ago
Help please............
tigry1 [53]

Answer:

\tan(J) =\frac{5\sqrt{66}}{66}

Step-by-step explanation:

\tan(J) =\frac{5}{\sqrt{66}}

\tan(J) =\frac{5}{\sqrt{66}} \times \frac{\sqrt{66}}{\sqrt{66}}

\tan(J) =\frac{5\sqrt{66}}{\sqrt{66}\times\sqrt{66} }

\tan(J) =\frac{5\sqrt{66}}{66}

5 0
3 years ago
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