9514 1404 393
Answer:
yes
Step-by-step explanation:
The figure can be shown to be a parallelogram by showing the sum of endpoints of the diagonals is the same.
A +C = B +D
(0, 6) +(0, -4) = (0, 2) = (3, 5) +(-3, -3) . . . . diagonals bisect each other
If the diagonals of a quadrilateral bisect each other, it is a parallelogram. A parallelogram with a right angle is a rectangle. So, ABCD is a rectangle.
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<em>Additional comment</em>
The midpoint of each diagonal is half the sum of the end point coordinates. That is, the midpoints are (0, 2)/2 = (0, 1). Since calculation of the midpoints requires both sums be divided by 2, we can tell the midpoints are the same if the sums are the same.
so I don't know but just use the internet
Answer:
I believe it's the 3rd awnser
Find the mean, median, mode, and range of this data: 49, 49, 54, 55, 52, 49, 55. If necessary, round to the nearest tenth.
Zigmanuir [339]
The mean is the average.
So, to find the mean you want o add up all of the numbers and then divide by the number of numbers.
49 + 49 + 54 + 55 + 52 + 49 + 575 = 363
363 / 7 = 51.85
Rounded to 52
For the median you want o line all of your number up from least to greatest and then find the middle number.
49,49,49,52,54,55,55
Your median is 52
The mode is the number that is listed most often
49 is listed 3 times
54 is listed 1 time
52 is listed 1 time
55 is listed 2 times
So, your mode is 49