If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y = 
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 = 
Cancel the C in both side
1/2 = 
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
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Answer:
210
Step-by-step explanation:
first I took 120 and divided by four to show how many cupcakes he can make in thirty minutes (.5 of an hour). this was 30. the reason we divided by four is because in two hours theres four halves.
120÷4=30 for half an hour
30x2=60 this is how many cupcakes he can make in one hour
since we already know how many he makes in two hours we're going to use that
120+60=180 (three hours)
120+60=180 (three hours)180+30 (half an hour) =210