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timurjin [86]
3 years ago
7

A baker can make 120 cupcakes in 2 hours. At that rate, how many cupcakes can he make in 3.5 hours? *

Mathematics
1 answer:
Valentin [98]3 years ago
4 0

Answer:

210

Step-by-step explanation:

first I took 120 and divided by four to show how many cupcakes he can make in thirty minutes (.5 of an hour). this was 30. the reason we divided by four is because in two hours theres four halves.

120÷4=30 for half an hour

30x2=60 this is how many cupcakes he can make in one hour

since we already know how many he makes in two hours we're going to use that

120+60=180 (three hours)

120+60=180 (three hours)180+30 (half an hour) =210

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pickupchik [31]

Answer:

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Step-by-step explanation:

So we have the expression:

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(x^2)(4x+5)+(-3x)(4x+5)+(-2)(4x+5)

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1. Write the word sentence as an equation. 2. Then solve the equation. 5/7a=25
seropon [69]

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Step-by-step explanation:

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harina [27]

Answer:

a

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b

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c

      \lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }

Step-by-step explanation:

From the question we are told that

    \frac{dy}{y} =  -\beta dt

Now integrating both sides

     ln y  =  \beta t + c

Now taking the exponent of both sides

       y(t) =  e^{\beta t + c}

=>     y(t) =  e^{\beta t} e^c

Let  e^c =  C

So

      y(t) = C e^{\beta t}

Now  from the question we are told that

      y(0) =  y_o

Hence

        y(0) = y_o  = Ce^{\beta * 0}

=>     y_o = C

So

        y(t) = y_o e^{\beta t}

From the question we are told that

      \frac{dx}{dt}  = -\alpha xy

substituting for y

      \frac{dx}{dt}  = - \alpha x(y_o e^{-\beta t })

=>   \frac{dx}{x}  = -\alpha y_oe^{-\beta t} dt

Now integrating both sides

         lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c

Now taking the exponent of both sides

        x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}

=>     x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c

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    \lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }

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Answer:

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