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frez [133]
3 years ago
8

The perimeter of a triangle is 240. Its sides are proportional to 3:4:5. The largest side of the triangle is

Mathematics
1 answer:
Basile [38]3 years ago
3 0
3n +4n +5n = 240
12n = 240
n = 240/12

n = 20

the length of sides of this triangle will be 

3*20=60
4*20=80
5*20=100

bc. 60+80+100 = 140+100=240

hope helped 
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\text{Area of the figure}=54\text{ unit}^2

Step-by-step explanation:

Please find the attachment.

Let us divide our given image in several parts and then we will find area of different parts.

First of all let us find the area of our red rectangle with side lengths 6 units and 7 units.

\text{Area of rectangle}=\text{Length*Width}

\text{Area of red rectangle part}=6\text{ units}\times 7\text{ units}

\text{Area of red rectangle part}=42\text{ units}^2

Now let us find area of yellow triangle on the top of red rectangle. We can see that base of triangle is 6 units and height is 1 unit.

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\text{Area of triangle}=3\text{ unit}^2

Let us find the area of green triangle.

\text{Area of green triangle}=\frac{1}{2}\times \text{3 units *2 units}

\text{Area of green triangle}=3\text{ unit}^2

Now we will find the area of blue triangle, whose base is 6 units and height is 2 units.

\text{Area of blue triangle}=\frac{1}{2}\times \text{6 units *2 units}

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\text{Area of the figure}=42\text{ units}^2+3\text{ unit}^2+3\text{ unit}^2+6\text{ unit}^2

\text{Area of the figure}=(42+3+3+6)\text{ unit}^2

\text{Area of the figure}=54\text{ unit}^2

Therefore, area of our given figure is 54 square units.  

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