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Svetach [21]
3 years ago
5

Pleas help me for 90 points

Mathematics
2 answers:
GaryK [48]3 years ago
8 0

Answer:

140 in²

Answer as a decimal rounded to the nearest hundredth = 140.00 in²

Step-by-step explanation:

Area of a triangle = 1/2 × base × height

Given:

  • base = 20 in
  • height = 14 in

Substituting the given values into the formula:

⇒ Area = 1/2 × 20 × 14

             = 140 in²

Answer as a decimal rounded to the nearest hundredth = 140.00 in²

BARSIC [14]3 years ago
4 0

Answer:

140 square inches

Step-by-step explanation:

Formula to find the area of a triangle is A = 1/2 × b × h.

So plug in the numbers

A= 1/2 x 20 x 14

A= 20 x 14 / 2

A = 280/ 2

A(Area) is equal to 140 square inches

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Answer:

m = 11/9

Step-by-step explanation:

m = (y2 - y1) / (x2 - x1)

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Scrat [10]

Answer:

P(x) = x³ - 3x² - 5x + 15

Step-by-step explanation:

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∴ P(x) = (x - √5)(x + √5)(x - 3)

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In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the<br> function with its graph
MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

f(x)=(x-2)^{2}+1

45)

The function g(x) is given by:

g(x)=f(x-1)

using f(x) we can find f(x-1)

g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

g(x)'=2(x-3)

2(x-3)=0

x=3

Puting it on g(x) we will get y value.

y=g(3)=(3-3)^{2}+1

y=g(3)=1

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

g(x)=f(x+2)

g(x)=((x+2)-2)^{2}+1

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Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2x

0=2x

x=0

Evaluatinf g(x) at this value of x we have:

g(0)=(x)^{2}+1

g(0)=1

<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

g(x)=f(x)+2

g(x)=(x-2)^{2}+1+2

g(x)=(x-2)^{2}+3

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}+3

g(2)=3

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48)

Let's use the same method here.

g(x)=f(x)-3

g(x)=(x-2)^{2}+1-3

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Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}-2

g(2)=-2

<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

<u />

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