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mina [271]
3 years ago
8

At a basketball game, 55% of people attending were supporting the home team, while

Mathematics
1 answer:
shusha [124]3 years ago
5 0

Answer:

286

Step-by-step explanation:

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What are two equivalent equations for<br> x(5x-6)+13x-10
Naily [24]
5x^2 +7x -10

5x^2 (-6x + 13x) - 10
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a farmer is putting up a rectangular pasture. it measures 320 feet by 335 feet it costs $8 per foot, how much will it cost
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Answer:

I think it would cost $13,400

Step-by-step explanation:

if you do 320 times 335 you get 107200 and then if you divide that by 107,200 you get $13,400

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Simplify.<br> -2(y+3)+4y
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The correct answer is 2y-6 let me know if you want to know how I got that
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Given the explicit formula for an srithmetic sequence find the first five terms and the 52nd term
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5.16 6.77 8.96.8u .987

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4 years ago
Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
3 years ago
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