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3 years ago

given two angles that measure 50 and 80 and a side that measures 4 feet how many triangles if any can be constucted

Mathematics

1 answer:

Ierofanga [76]3 years ago

3 0

There is only one triangle possible having angle 50, 50, 80.

<h3>What is isosceles triangle?</h3>

An Isosceles Triangle has the following properties:

Two sides are congruent to each other.
The third side of an isosceles triangle which is unequal to the other two sides is called the base of the isosceles triangle.

The two angles opposite to the equal sides are congruent to each other.

It is given that, 2 angles of a triangle as:

∠1 = 50°

∠2 = 80°

Now we know the Angle sum property of a triangle that sum all three interior angle in a triangle is $180^{0}$ .

i.e., ∠1+∠2+∠3= $180^{0}$ .

So, 50° +80°+ ∠3 = $180^{0}$

∠3 = 50°

As two angles of the triangle are equal that means it is a isosceles triangle.

There is no possibility of getting a right angles triangle.

Hence, there is only one triangle possible with these measurements .

Learn more about triangles here:

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How do you find the limit?

coldgirl [10]

Answer:

2/5

Step-by-step explanation:

Hi! Whenever you find a limit, you first directly substitute x = 5 in.

$\displaystyle \large{ \lim_{x \to 5} \frac{x^2-6x+5}{x^2-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{5^2-6(5)+5}{5^2-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{25-30+5}{25-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{0}{0}}$

Hm, looks like we got 0/0 after directly substitution. 0/0 is one of indeterminate form so we have to use another method to evaluate the limit since direct substitution does not work.

For a polynomial or fractional function, to evaluate a limit with another method if direct substitution does not work, you can do by using factorization method. Simply factor the expression of both denominator and numerator then cancel the same expression.

From x²-6x+5, you can factor as (x-5)(x-1) because -5-1 = -6 which is middle term and (-5)(-1) = 5 which is the last term.

From x²-25, you can factor as (x+5)(x-5) via differences of two squares.

After factoring the expressions, we get a new Limit.

$\displaystyle \large{ \lim_{x\to 5}\frac{(x-5)(x-1)}{(x-5)(x+5)}}$

We can cancel x-5.

$\displaystyle \large{ \lim_{x\to 5}\frac{x-1}{x+5}}$

Then directly substitute x = 5 in.

$\displaystyle \large{ \lim_{x\to 5}\frac{5-1}{5+5}}\\

\displaystyle \large{ \lim_{x\to 5}\frac{4}{10}}\\

\displaystyle \large{ \lim_{x\to 5}\frac{2}{5}=\frac{2}{5}}$

Therefore, the limit value is 2/5.

L’Hopital Method

I wouldn’t recommend using this method since it’s too easy but only if you know the differentiation. You can use this method with a limit that’s evaluated to indeterminate form. Most people use this method when the limit method is too long or hard such as Trigonometric limits or Transcendental function limits.

The method is basically to differentiate both denominator and numerator, do not confuse this with quotient rules.

So from the given function:

$\displaystyle \large{ \lim_{x \to 5} \frac{x^2-6x+5}{x^2-25}}$

Differentiate numerator and denominator, apply power rules.

Differential (Power Rules)

$\displaystyle \large{y = ax^n \longrightarrow y\prime= nax^{n-1}$

Differentiation (Property of Addition/Subtraction)

$\displaystyle \large{y = f(x)+g(x) \longrightarrow y\prime = f\prime (x) + g\prime (x)}$

Hence from the expressions,

$\displaystyle \large{ \lim_{x \to 5} \frac{\frac{d}{dx}(x^2-6x+5)}{\frac{d}{dx}(x^2-25)}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{\frac{d}{dx}(x^2)-\frac{d}{dx}(6x)+\frac{d}{dx}(5)}{\frac{d}{dx}(x^2)-\frac{d}{dx}(25)}}$

Differential (Constant)

$\displaystyle \large{y = c \longrightarrow y\prime = 0 \ \ \ \ \sf{(c\ \ is \ \ a \ \ constant.)}}$

Therefore,

$\displaystyle \large{ \lim_{x \to 5} \frac{2x-6}{2x}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{2(x-3)}{2x}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{x-3}{x}}$

Now we can substitute x = 5 in.

$\displaystyle \large{ \lim_{x \to 5} \frac{5-3}{5}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{2}{5}}=\frac{2}{5}$

Thus, the limit value is 2/5 same as the first method.

Notes:

If you still get an indeterminate form 0/0 as example after using l’hopital rules, you have to differentiate until you don’t get indeterminate form.

8 0

3 years ago

ally needs to make a cake that hs to be 48 inches long but she already has 1/2 inches done how much more dose she have left to m

FromTheMoon [43]

24. you divide 48 by 2 to get the answer

5 0

3 years ago

Read 2 more answers

The cost in dollars of making x items is given by the function C(x)=10x+800.

Bogdan [553]

C(x) = 10x+500

A. C(O)=A 10.0+500. = 500.e

B. C(25) = 10.25+500 =750

C.c(x)=1500=10x+500

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3 years ago

Analyze the table below and answer the question that follows.

lora16 [44]

Answer:

C. Events E and A are independent

Step-by-step explanation:

we will verify each options

(a)

We can use independent events formula

P(B∩C)=P(B)*P(C)

we are given

P(B)=0.4

P(C)=0.25

P(B∩C)=0.05

now, we can plug these values into formula

and we get

0.05=0.4*0.25

0.05=0.1

we can see that left side is not equal to right side

so, this is FALSE

(b)

We can use independent events formula

P(D∩A)=P(D)*P(A)

we are given

P(D)=0.25

P(A)=0.6

P(D∩A)=0.1

now, we can plug these values into formula

and we get

0.1=0.25*0.6

0.1=0.15

we can see that left side is not equal to right side

so, this is FALSE

(c)

We can use independent events formula

P(E∩A)=P(E)*P(A)

we are given

P(E)=0.5

P(A)=0.6

P(E∩A)=0.3

now, we can plug these values into formula

and we get

0.3=0.5*0.6

0.3=0.3

we can see that both sides are equal

so, this is TRUE

(d)

We can use independent events formula

P(D∩B)=P(D)*P(B)

we are given

P(D)=0.25

P(B)=0.4

P(D∩A)=0.15

now, we can plug these values into formula

and we get

0.15=0.25*0.4

0.15=0.1

we can see that left side is not equal to right side

so, this is FALSE

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3 years ago

Does anyone know this?! the answers are a- 0.12 b- 0.32 c-0.20 d.0.08

Tanya [424]

Answer:

Step-by-step explanation:

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3 years ago