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Nostrana [21]
3 years ago
7

Analyze the table below and answer the question that follows.

Mathematics
1 answer:
lora16 [44]3 years ago
8 0

Answer:

C. Events E and A are independent

Step-by-step explanation:

we will verify each options

(a)

We can use independent events formula

P(B∩C)=P(B)*P(C)

we are given

P(B)=0.4

P(C)=0.25

P(B∩C)=0.05

now, we can plug these values into formula

and we get

0.05=0.4*0.25

0.05=0.1

we can see that left side is not equal to right side

so, this is FALSE

(b)

We can use independent events formula

P(D∩A)=P(D)*P(A)

we are given

P(D)=0.25

P(A)=0.6

P(D∩A)=0.1

now, we can plug these values into formula

and we get

0.1=0.25*0.6

0.1=0.15

we can see that left side is not equal to right side

so, this is FALSE

(c)

We can use independent events formula

P(E∩A)=P(E)*P(A)

we are given

P(E)=0.5

P(A)=0.6

P(E∩A)=0.3

now, we can plug these values into formula

and we get

0.3=0.5*0.6

0.3=0.3

we can see that both sides are equal

so, this is TRUE

(d)

We can use independent events formula

P(D∩B)=P(D)*P(B)

we are given

P(D)=0.25

P(B)=0.4

P(D∩A)=0.15

now, we can plug these values into formula

and we get

0.15=0.25*0.4

0.15=0.1

we can see that left side is not equal to right side

so, this is FALSE


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nika2105 [10]

Answer:

6= 66.67%

7=25%

8=70%

6 0
3 years ago
Which of the following is not a valid conversion factor?
inessss [21]

Answer:

Out of the 3 that were listed, the "conversion" that is invalid is 1 meter = 10 millimeters.

Step-by-step explanation:

First: Well, for something like this, you don't really need steps, you just need to know how to do process of elimination and also your conversions:

We know that 1 meter is 100 centimeters

We know 1 kilometer is 1000 meters

We know that 1 meter is 10 millim....... Wait. Do we know that?

No! 1 meter is not 10 millimeters, it's 1000 millimeters. So 1 meter = 10 millimeters is invalid.

If you ever need a converter, use this link: https://www.google.com/search?q=centimeters+to+inches&rlz=1CAFQZI_enCA835&oq=centim&aqs=chrome.2.69i57j0l5.9328j0j7&sourceid=chrome&ie=UTF-8

Thank you for reading

Topic: Metric Conversions

4 0
3 years ago
Read 2 more answers
What are the solutions of the equation x4 – 5x2 – 36 = 0? Use factoring to solve.
pentagon [3]

Answer:

x=+/-3

Step-by-step explanation:

x^4-5x^2-36=0

factor

(x^2-9)(x^2+4)=0

split into 2 equations because one of these terms will need to equal zero for the eqation to be true

x^2-9=0              x^2+4=0

x^2=9                    x^2=-4

x=+/-3                    no real numbers

7 0
3 years ago
In which of the options below will the number 3 correctly fill in the blank. Select all that apply. A) ___ : 4 = 12 : 16 B) 1 :
aniked [119]

Answer:

A and B

Step-by-step explanation:

Given

List of given options

Required

Which will correctly take 3 to fill the blank

Represent the blanks with x

Option A:

x : 4 = 12 : 16

Convert to fractions

\frac{x}{4} = \frac{12}{16}

Multiply through by 4

4 * \frac{x}{4} = 4 * \frac{12}{16}

x = \frac{48}{16}

x = 3

Option B:

1 : 5= x : 15

Convert to fraction;

\frac{1}{5} = \frac{x}{15}

Multiply through by 15

15 * \frac{1}{5} = \frac{x}{15} * 15

15 * \frac{1}{5} = x

3 = x

x = 3

Option C:

x : 1 = 12 : 3

Convert to fraction

\frac{x}{1} = \frac{12}{3}

x = 4

Option D

15:x = 3:1

Convert to fraction

\frac{15}{x} = \frac{3}{1}

Cross Multiply

3 * x = 15 * 1

3 * x = 15

Divide through by 3

x = 5

From the above calculations.

<em>Option A and B can be filled with 3</em>

5 0
3 years ago
100 points! simplify write as a product compute
Rom4ik [11]

Answer:

a) \sqrt{61 - 24 \sqrt{5} }  =  - 4  + 3 \sqrt{5}

b)( \sqrt{ ( {c}^{2}   -  1) ({b}^{2}    -  1) } - {2 \sqrt{bc} }) (\sqrt{ ( {c}^{2}   -  1) ({b}^{2}    -  1) }  + {2 \sqrt{bc}  } )

c) \frac{ \sqrt{9 - 4 \sqrt{5} } }{2 -  \sqrt{5} }  =   - 1

Step-by-step explanation:

We want to simplify

\sqrt{61 - 24 \sqrt{5} }

Let :

\sqrt{61 - 24 \sqrt{5} }  = a - b \sqrt{5}

Square both sides of the equation:

(\sqrt{61 - 24 \sqrt{5} } )^{2}  =  ({a - b \sqrt{5} })^{2}

Expand the RHS;

61 - 24 \sqrt{5} =  {a}^{2}  - 2ab \sqrt{5}  + 5 {b}^{2}

Compare coefficients on both sides:

{a}^{2}  + 5 {b}^{2}  = 61 -  -  - (1)

- 24 =  - 2ab \\ ab = 12 \\ b =  \frac{12}{b}  -  -  -( 2)

Solve the equations simultaneously,

\frac{144}{ {b}^{2} }  + 5 {b}^{2}  = 61

5 {b}^{4}  - 61 {b}^{2}  + 144 = 0

Solve the quadratic equation in b²

{b}^{2}  = 9 \: or \:  {b}^{2}  =  \frac{16}{5}

This implies that:

b =  \pm3 \: or \: b =  \pm  \frac{4 \sqrt{5} }{5}

When b=-3,

a =  - 4

Therefore

\sqrt{61 - 24 \sqrt{5} }  =  - 4  + 3 \sqrt{5}

We want to rewrite as a product:

{b}^{2}  {c}^{2}  - 4bc -  {b}^{2}  -  {c}^{2}  + 1

as a product:

We rearrange to get:

{b}^{2}  {c}^{2}   -  {b}^{2}  -  {c}^{2}  + 1- 4bc

We factor to get:

{b}^{2} ( {c}^{2}   -  1)  -  ({c}^{2}   -  1)- 4bc

Factor again to get;

( {c}^{2}   -  1) ({b}^{2}   -  1)- 4bc

We rewrite as difference of two squares:

(\sqrt{( {c}^{2}   -  1) ({b}^{2}   -  1) })^{2} - ( {2 \sqrt{bc} })^{2}

We factor the difference of square further to get;

( \sqrt{ ( {c}^{2}   -  1) ({b}^{2}    -  1) } - {2 \sqrt{bc} }) (\sqrt{ ( {c}^{2}   -  1) ({b}^{2}    -  1) }  + {2 \sqrt{bc}  } )

c) We want to compute:

\frac{ \sqrt{9 - 4 \sqrt{5} } }{2 -  \sqrt{5} }

Let the numerator,

\sqrt{9 - 4 \sqrt{5} }  = a - b \sqrt{5}

Square both sides of the equation;

9 - 4 \sqrt{5}  =  {a}^{2}  - 2ab \sqrt{5}  + 5 {b}^{2}

Compare coefficients in both equations;

{a}^{2}  + 5 {b}^{2}  = 9 -  -  - (1)

and

- 2ab =  - 4 \\ ab = 2 \\ a =  \frac{2}{b}  -  -  -  - (2)

Put equation (2) in (1) and solve;

\frac{4}{ {b}^{2} }  + 5 {b}^{2}  = 9

5 {b}^{4}   - 9 {b}^{2}  + 4 = 0

b =  \pm1

When b=-1, a=-2

This means that:

\sqrt{9 - 4 \sqrt{5} }  =  - 2 +  \sqrt{5}

This implies that:

\frac{ \sqrt{9 - 4 \sqrt{5} } }{2 -  \sqrt{5} }  =  \frac{ - 2 +  \sqrt{5} }{2 -  \sqrt{5} }  =  \frac{ - (2 -  \sqrt{5)} }{2 -  \sqrt{5} }  =  - 1

3 0
3 years ago
Read 2 more answers
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