Answer:
The dimensions are:
by 
Step-by-step explanation:
The area of the rectangle is given as

The factored form of this quadratic trinomial gives the dimensions of the rectangle.
We factor 3 first to obtain;

We split the middle term to get;

We factor within the parenthesis to get;

We factor further to get;

The dimensions are:
by 
Then the perimeter will be

Answer:
f(x)=3x-5
g(x)=-6x²+6x+2
f(x)×g(x)
=(3x-5)(-6x²+6x+2)( use distributive property)
=(3x×-6x²)+(3x×6x)+(3x×2)+(-5×-6x²)+(-5×6x)+(-5×2)
=(-18x³)+(18x²)+6x+30x²-30x-10
=-18x³+18x²+6x-30x+30x²-10
=-18x³+18x²-24x+30x²-10
=-18x³+18x²+30x²-10
=-18x³+48x²-10---------------you may write this answer
Hope it's was clear,
please pick me brainliest
9514 1404 393
Answer:
11 cm by 33 cm
Step-by-step explanation:
You can solve this problem mentally as follows.
Consider the rectangle as 3 squares, side-by-side. Then the area of each of those squares is 363/3 = 121 cm^2. From your knowledge of the squares of numbers, you know that 121 = 11^2. So, the width of the rectangle is 11 cm, and the length is 3 times that, or 33 cm.
_____
Using variables, we can let w represent the width. Then 3w can represent the length, and the area is ...
A = LW
A = (3w)(w) = 3x^2 = 363
w^2 = 363/3 = 121
w = √121 = 11
3w = 3·11 = 33
The width is 11 cm; the length is 33 cm.
AO = 21
BC = 14
OC = radius of the circle = AO = 21
∴ OB = OC + CB = 21 + 14 = 35
<span>Line AB is tangent to circle O at A</span>
∴ AB is perpendicular to AO
∴ Δ OAB is a right triangle at A
Applying Pythagorean theorem
∴ OB² = AO² + AB²
∴ AB² = OB² - AO² = 35² - 21² = 1225 - 441 = 784
∴ AB = √784 = 28
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