3 years ago

Write the equation of the line that is perpendicular to y=2x-7 that passes through (3,1)

Mathematics

1 answer:

Finger [1]3 years ago

8 0

Answer:

y=-1/2x-1/2

Step-by-step explanation:

For this, you need to use the point slope formula, (y-y1)=m(x-x1). The slope, m, would be -1/2 since the line we're looking for is perpendicular (meaning the slope is the negative reciprocal of the original slope). The x1 would be 3, and the y1 would be 1.

(y-y1)=m(x-x1)

(y-1)=-1/2(x-3)

y-1=-1/2x-3/2

y=-1/2x-1/2

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Okay, what is x if: -7/9 (x 3) =14?

Charra [1.4K]

I hope this helps you

-7.x^3=2.7.9

x^3=-18

x=i.(3square root of 18)

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3 years ago

in abbys grade, there 70 students. currently, 10% of them are enrolled in health. how many students are enrolled in health?

goblinko [34]

Answer:

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Step-by-step explanation:

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3 years ago

Please help i really need help <br> thanks

Grace [21]

Answer:

B. 31.62

Step-by-step explanation:

First, find the distance of the line using the distance formula, $d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1} )^2 }$ . Plug the two points (-1,0) and (5,2) into the formula and solve. This gives you 6.32, then this is only one line of a pentagon, which has 5 sides, so you need to multiply. Since you are finding the perimeter, which is all of the sides added together, multiply the one side by 5. 6.32*5=31.62.