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3 years ago

Write the equation of the line that is perpendicular to y=2x-7 that passes through (3,1)

Mathematics

1 answer:

Finger [1]3 years ago

8 0

Answer:

y=-1/2x-1/2

Step-by-step explanation:

For this, you need to use the point slope formula, (y-y1)=m(x-x1). The slope, m, would be -1/2 since the line we're looking for is perpendicular (meaning the slope is the negative reciprocal of the original slope). The x1 would be 3, and the y1 would be 1.

(y-y1)=m(x-x1)

(y-1)=-1/2(x-3)

y-1=-1/2x-3/2

y=-1/2x-1/2

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krek1111 [17]

Answer: Friday

Step-by-step explanation:

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2 years ago

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Musya8 [376]

Answer:

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Step-by-step explanation:

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2 years ago

What is the solution to the following system?

katrin2010 [14]

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Step-by-step explanation:

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3 years ago

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Vedmedyk [2.9K]

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3 years ago

WILL MEDAL help me if please

nordsb [41]

1. Use the FOIL method (x+9)(x+9)
First, outer, inner, last
$x^{2} +9x+9x+81$
Add your like terms
$x^{2} +18x+81$

2. When you add or subtract polynomials you add or subtract the like terms and then put them in order from largest to smallest exponents.

3. $-5x(5 x^{3} +10 x^{2} -6x+3)$

4. Since it is the perimeter, we add the 3 together.
$(2 x^{2} +4x-3)+(-3 x^{2} -3)+(5x+19)$
Add the like terms together:
$2 x^{2} +(-3 x^{2} )=- x^{2} \\ 4x+5x=9x \\ -8+(-3)+19=8$
Put them in order of exponents
$- x^{2} +9x+8$

Hope this helps

8 0

3 years ago