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nataly862011 [7]

2 years ago

14

What does a small MAD tell you about a set of data

1 answer:

Karolina [17]2 years ago

3 0

The larger the MAD, the less relevant is the mean as an indicator of the values within the set.

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Which equations are equivalent to ? 3^3√x+4 =12 Check all that apply.

eimsori [14]

Answer:

option c

x + 4 = 64

and

option e

x = 60

Step-by-step explanation:

Given in the question an expression

3∛x+4 = 12

∛x + 4 = 12/3

∛x + 4 = 4

Take cube on both sides of the equation

∛(x + 4)³ = 4³

x + 4 = 64

x = 64 - 4

x = 60

4 0

2 years ago

Read 2 more answers

Evaluate the following pic

GREYUIT [131]

Answer:

1) $\sqrt{1225}+\sqrt{1024}=67$

2) $\sqrt[3]{-1331}=-11$

3) Evaluating $2:p :: p:8$ we get $p=\pm 4$

4) $x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}$

5) $\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6$

Step-by-step explanation:

1) $\sqrt{1225}+\sqrt{1024}$

Prime factors of 1225 : 5x5x7x7

Prime factors of 1024: 2x2x2x2x2x2x2x2x2x2

$\sqrt{1225}+\sqrt{1024}\\=\sqrt{5\times5\times7\times7}+\sqrt{2\times2\times2\times2\times2\times2\times2\times2\times2\times2}\\=\sqrt{5^2\times7^2}+\sqrt{2^2\times2^2\times2^2\times2^2\times2^2}\\=5\times7+(2\times2\times2\times2\times2)\\=35+32\\=67$

$\sqrt{1225}+\sqrt{1024}=67$

2) $\sqrt[3]{-1331}$

We know that $\sqrt[n]{-x}=-\sqrt[n]{x} \ ( \ if \ n \ is \ odd)$

Applying radical rule:

$\sqrt[3]{-1331}\\=-\sqrt[3]{1331} \\=-\sqrt[3]{11\times\11\times11}\\=-\sqrt[3]{11^3} \\Using \ \sqrt[n]{x^n}=x \\=-11$

So, $\sqrt[3]{-1331}=-11$

3) $2:p :: p:8$

It can be written as:

$p*p=2*8\\p^2=16\\Taking \ square \ root \ on \ both \ sides\\\sqrt{p^2}=\sqrt{16}\\p=\pm 4$

Evaluating $2:p :: p:8$ we get $p=\pm 4$

4) $x^3+y^2+z \ when \ x=3, y=-2, x=-6$

Put value of x, y and z in equation and solve:

$x^3+y^2+z \\=(3)^3+(-2)^2+(-6)\\=27+4-6\\=25$

So, $x^3+y^2+z \ when \ x=3, y=-2, x=-6 \ we \ get \ \mathbf{25}$

5) $\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}$

We know (-a)^n = (a)^n when n is even and (-a)^n = (-a)^n when n is odd

$\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}\\\\=\frac{1296\times-8\times 27}{46656}\\\\=\frac{-279936}{46656} \\\\=-6$

So, $\frac{(-6)^4\times(-2)^3\times(3)^3}{(-6)^6}=-6$

8 0

2 years ago

Need help solving homework

Lilit [14]

3 + 2 = 1 + 4
2 + 15 = 10 + 7
8 + 9 = 19 - 2
12 - 7 = 14 - 9

Hope this helped!

3 0

2 years ago

Read 2 more answers

Which statement decribes the ratio 13:8?

Mamont248 [21]

Answer:

D

Step-by-step explanation:

that what I think but not sure

4 0

3 years ago

Read 2 more answers

Simon drove through some roadworks where the speed limit was 50 mph. Two cameras recorded the time taken to travel 1200 m throug

Tom [10]

Answer:

$Speed = 21.43m/s$

Step-by-step explanation:

Given

$Distance = 1200m$ -- of the roadworks

$Time\ Recorded = 56s$

Required

Determine the speed

In this case:

$Speed = \frac{Distance\ of\ Roadword}{Time\ Captured}$

$Speed = \frac{1200m}{56s}$

<em></em> $Speed = 21.43m/s$ <em> --- approximated</em>

3 0

2 years ago