Answer:
Option D is the correct option.
<em>please </em><em>see</em><em> the</em><em> attached</em><em> picture</em><em> for</em><em> full</em><em> solution</em><em>.</em><em>.</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>
7 7/9
chamge 11 2/3 to improper faction and multiply <span />
<h3>Answer: A. 5/12, 25/12</h3>
============================
Work Shown:
12*sin(2pi/5*x)+10 = 16
12*sin(2pi/5*x) = 16-10
12*sin(2pi/5*x) = 6
sin(2pi/5*x) = 6/12
sin(2pi/5*x) = 0.5
2pi/5*x = arcsin(0.5)
2pi/5*x = pi/6+2pi*n or 2pi/5*x = 5pi/6+2pi*n
2/5*x = 1/6+2*n or 2/5*x = 5/6+2*n
x = (5/2)*(1/6+2*n) or x = (5/2)*(5/6+2*n)
x = 5/12+5n or x = 25/12+5n
these equations form the set of all solutions. The n is any integer.
--------
The two smallest positive solutions occur when n = 0, so,
x = 5/12+5n or x = 25/12+5n
x = 5/12+5*0 or x = 25/12+5*0
x = 5/12 or x = 25/12
--------
Plugging either x value into the expression 12*sin(2pi/5*x)+10 should yield 16, which would confirm the two answers.
Answer:
BC = 2
Step-by-step explanation:
We first need to use triangle BAD to find BD,
BD is the hypotenuse, so use pythagorean theorem...
(√23)² + (√13)² = (BD)²
23 + 13 = (BD)²
36 = (BD)²
6 = BD
Now BD is the hypotenuse of triangle BCD, so use pythagorean theorem agian to find BC
(4√2)² + (BC)² = 6²
32 + (BC)² = 36
(BC)² = 4
BC = 2
