Answer:
8 one-dollar bills
3 five-dollar bills
2 ten-dollar bills
Step-by-step explanation:
Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13
x + 5y + 10z = 43
x = 4z
x + y + z = 13
x + 5y + 10z = 43
x + 0y - 4z = 0
x + y + z = 13
5y + 14z = 43
-y - 5z = -13
5y + 14z = 43
-5y - 25z = -65
-11z = -22
z = 2
x = 4z
x = 4*2 = 8
x + y + z = 13
8 + y + 2 = 13
10 + y = 13
y = 3
Answer:
21/40, 17/20, 29/40, 3/4, 4/5
Step-by-step explanation:
21/40 = 10.5/20
29/40 = 14.5/20
17/20 = 13.5/20
3/4 = 15/20
4/5 = 16/20
In order to develop an equation, let's use the slope-intercept form of the linear equation:
Using the points (3, 13.5) and (5, 18.5) from the table, we have:
Subtracting the second and the first equation:
Now, finding the value of b:
So the equation that represents this table is y = 2.5x + 6
Looking at the options, the correct one is E (none of the above).
Answer:
Probability distribution
X P(X)
0 1/8
1 3/8
2 3/8
3 1/8
Step-by-step explanation:
When a coin is tossed there are two outcomes head and tail. When three coins are tossed the possible outcomes are
Sample space=S={HTH,THH,TTH,HHH,HTT,THT,TTT,HHT}
The total number of outcomes is n(S)=8. The X be the random variable counting number of tails in each outcome and so X can take values as 0,1,2,3. The probabilities can be computed as P(X)=n(X)/n(S). The probabilities are calculated as under:
X Outcomes P(X)
0 HHH 1/8
1 HHT,THH,HTH 3/8
2 TTH,HTT,THT 3/8
3 TTT 1/8
The probability distribution of X is as under:
X P(X)
0 1/8
1 3/8
2 3/8
3 1/8
