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NARA [144]
3 years ago
13

Find the area of a regular triangle with side length of 15.5 inches

Mathematics
1 answer:
Ganezh [65]3 years ago
5 0

Answer:

Brainliest pls

Step-by-step explanation:

A≈104.03in²

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3 years ago
Cos s=-2/5 and sin t=4/5, s and t are in quadrant II<br> find cos(s+t) and cos(s-t)
mojhsa [17]

Answer:

•cos(s+t) = cos(s)cos(t) - sin(s)sin(t) = (-⅖).(-⅗) - (√21 /5).(⅘) = +6/25 - 4√21 /25 = (6-4√21)/25

•cos(s-t) = cos(s)cos(t) + sin(s)sin(t) = (-⅖).(-⅗) + (√21 /5).(⅘) = +6/25 + 4√21 /25 = (6+4√21)/25

cos(t) = ±√(1 - sin²(t)) → -√(1 - sin²(t)) = -√(1 - (⅘)²) = -⅗

sin(s) = ±√(1 - cos²(s)) → +√(1- cos²(s)) = +√(1 - (-⅖)²) = √21 /5

5 0
3 years ago
A store advertises 15% off an item that regularly sells $300.what is the sale price off the item?
Komok [63]
The original price of the item is said to be 100 dollars.
Now, it offers 15% discount. Let's solve for the dicounted price.
=> 15% = 0.15
Solution:
=> 300 * .15 
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3 0
3 years ago
Read 2 more answers
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I am sorry but i don't no
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