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NARA [144]
2 years ago
13

Find the area of a regular triangle with side length of 15.5 inches

Mathematics
1 answer:
Ganezh [65]2 years ago
5 0

Answer:

Brainliest pls

Step-by-step explanation:

A≈104.03in²

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Among all students, sports is, by far, the most popular activity and watching TV is the least popular.
3 0
3 years ago
PLease send explanation.
Svetach [21]

Answer:

Step-by-step explanation:

XY = 1/2 * QR (According to the midpoint theorem)

=1/2 * 15.6

=15.6/2

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7 0
2 years ago
Read 2 more answers
I have 200 coins to put into 4 bags I put the coins into each bag so that each bag has 2 mote coins than the one before How many
Allushta [10]

First bag has 47 coins and second bag has 49 coins and third bag has 51 coins and fourth bag has 53 coins

<em><u>Solution:</u></em>

Given that,

Total number of coins = 200

Number of bags = 4

<em><u>I put the coins into each bag so that each bag has 2 more coins than the one before</u></em>

Therefore,

Each bag has 2 more coins than the one before. Based on this we can say,

Let "x" be the number of coins put in first bag

Then, x + 2 is the number of coins put in second bag

Then, x + 4 is the number of coins put in third bag

Then, x + 6 is the number of coins put in fourth bag

We know that,

Total number of coins = 200

x + x + 2 + x + 4 + x + 6 = 200\\\\4x + 12 = 200\\\\4x = 200-12\\\\4x = 188\\\\x = 47

Thus,

Coins put in first bag = x = 47

Coins put in second bag = x + 2 = 47 + 2 = 49

Coins put in third bag = x + 4 = 47 + 4 = 51

Coins put in fourth bag = x + 6 = 47 + 6 = 53

Thus number of coins in each bag are found

4 0
3 years ago
Please answer this question
Vladimir [108]

Answer:

  • a = 3/2
  • b = -1/2

Step-by-step explanation:

  \dfrac{\sqrt{5}-1}{\sqrt{5}+1}=\dfrac{(\sqrt{5}-1)(\sqrt{5}-1)}{(\sqrt{5}+1)(\sqrt{5}-1)}\\\\=\dfrac{5-2\sqrt{5}+1}{5-1}=\dfrac{6-2\sqrt{5}}{4}\\\\=\dfrac{3}{2}-\dfrac{1}{2}\sqrt{5}

Comparing this to the form a+b√5, we see that ...

  a = 3/2

  b = -1/2

8 0
3 years ago
Find the value of :x^2+2xy+y^2-3x-3y-1<br> have: x^2-y=y^2-x (x<img src="https://tex.z-dn.net/?f=%5Cneq" id="TexFormula1" title=
lidiya [134]

Answer: The answer is x^2+2xy+2y^2–3x–3y–1

Step-by-step explanation: Move 2 to the left of y^2.

7 0
2 years ago
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