A sector of a circle is the portion of a disk enclosed by two radii and an arc, where the smaller area is known as the minor sector and the larger being the major sector.
The area A of a circle with radius r is given by A = πr2. The circumference C of that same circle is given by C = 2πr. But these are the formulas for the entire circle. Sometimes you will need to work with just a portion of a circle's revolution, or with many revolutions of the circle.

3 0

2 years ago

Point a pq and r are collinear on pr and pq: pr =2/3. P is located on the origin q is located at (x,y) and r is located at (-12,

dybincka [34]

The values of x and y are 8 and 0 respectively.

Explanation

As 'p' is located at (0,0) and 'r' is located at (-12,0) , that means both 'p' and 'r' are on the x-axis. So point 'q' will be also on the x-axis , and 'q' is located at (x,y)

So, the value of y will be 0. That means the co ordinate of point 'q' is (x, 0)

Now, using the Distance formula, length of 'pq' $= \sqrt{(x-0)^2 +(0-0)^2}= \sqrt{x^2}= x$

and length of 'pr' $= \sqrt{(-12-0)^2+(0-0)^2}= \sqrt{144}=12$

Given that, pq : pr =2/3

So....

$\frac{x}{12} =\frac{2}{3}\\ \\ 3x=24\\ \\ x= \frac{24}{3}=8$

Thus, the values of x and y are 8 and 0 respectively.

8 0

3 years ago

The expression(x 12) (y-13) (x-5) (y 4) is equivalent to xmxy. what is the value of n?

ANTONII [103]

Answer:

-9

Step-by-step explanation:

The applicable exponent rule is ...

a^b·a^c = a^(b+c)

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For the y factor, ...

y^-13 · y^4 = y^(-13+4) = y^-9 . . . . . exponent of -9

3 0

3 years ago