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o-na [289]
3 years ago
8

Please help me out please

Mathematics
1 answer:
ad-work [718]3 years ago
8 0

this is the answer, I guess.

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What is 1.96 rounded to the nearest tenth
a_sh-v [17]

Answer:

2

due to the thenth being higher than the number five i would say round up so 9 becomes a solid number so the answers 2




just remember:


it goes ones decimal tenths hundreths thosenths



as well as five or more raise the score for or less let it rest


sorry for mispelling words its not my greatest skill

4 0
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What is 24.79 x 4,022 pls
lozanna [386]

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24.79 \times 4022 \\  = 99705.38

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ipn [44]
-14i is the answer to the equation
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Gala2k [10]

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g (15 points) Suppose 42 out of 600 rats exposed to a potential carcinogen develop tumors. A control group of 350 rats not expos
vazorg [7]

Answer:

a) The relative risk is 1.8\overline{846153}

b) The attributable risk is 0.69 \overline{047619}

c) There is a relationship between exposure and tumor risk

Step-by-step explanation:

The number of exposed rats that develop tumors, a = 42

The number of rats exposed to the carcinogen = 600 rats

The number of exposed rats that did not develop tumors, b = 600 - 42 = 558

The number of not exposed rats in the control group = 350 rats

The number of rats that develop tumors in the control group, c = 13 tumors

The number of not exposed rats that did not develop tumors, d = 350 - 13 = 337  rats

a) The relative risk, RR = a/(a + b)/(c/(c + d))

∴ RR = (42/(42 + 558))/(13/(13 + 337)) = 49/26 = 1.8\overline{846153}

b) The attributable risk = (a - c)/a

∴ The attributable risk = (42 - 13)/42 = 0.69 \overline{047619}

c) The odds ratio = (a·b)/(c·d)

∴ The odds ratio = 42 × 558/(13 × 337) = 23439/4381 ≈ 5.35

Given that the result of attributable risk is positive, there is an indication that there is a higher probability to develop tumor when exposed to the potential carcinogen, therefore, there is a relationship between exposure and tumor risk

7 0
3 years ago
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