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masya89 [10]
2 years ago
7

13, 13, 85, 50, 79, 83 Mean Median Mode Range

Mathematics
2 answers:
Shtirlitz [24]2 years ago
6 0

Answer:

Mean-53.83

Median-64.5

Mode-13

Range-72

Step-by-step explanation:

wolverine [178]2 years ago
4 0
Mean : 53.83

median : 64.5

mode : 13

range : 72
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Can someone do this for me please?!
amm1812
<h3>What are the different parts of a circle? </h3>

The different parts of a circle are radius, diameter, chord, tangent, arc, centre, secant, sector. Write down the circle formulas. If “r” is the radius of the circle, then the formula for the area and the circumference of a circle are:

5 0
2 years ago
Select all the sets of ordered pairs that the graph of the equation y − 1 = −2(x − 2) contains.
ExtremeBDS [4]

<u>The sets of ordered pairs that the graph of the equation y − 1 = −2(x − 2) contains:</u>

  • (0, 5) and (−2, 9)
  • (−1, 7) and (2, 1)

Answer: Option B and C

<u>Step-by-step explanation:</u>

Given that  the equation of line is y - 1 = -2 (x - 2) . Now after solving the above equation, we can write the above equation as

                    y = - 2 x + 5

Substitute the coordinates of each set of given ordered pairs into the above equation to find out which belong to the graph of that given equation

A.(0, −2) and (1, 3)

-2 = -2(0)+5 which gives -2 = 5

3 = -2(1)+5 which gives 3=3 and denotes not contain the set of ordered pairs

B. (0, 5) and (−2, 9)

5 = -2(0)+5 which gives 5=5  

9= -2(-2)+5 which gives 9=9 and denotes the set of ordered pairs

C. (−1, 7) and (2, 1)

7 = -2(-1)+5 which gives 7=7

1 = -2(2 )+5 which gives 1=1 and denotes the set of ordered pairs

D. (3, −1) and (2, −1)

-1 = -2(3)+5 which gives -1 = -1

-1 = -2(2)+5 which gives -1 = 1 and denotes not contain the set of ordered pairs

E. (1, 2) and (4, 3)

2 = -2(1)+5 which gives 2 = 3

3 = -2(4)+5 which gives 3 = -3 and denotes not contain the set of ordered pairs

Now, the above equation is satisfied by the given options B and C as on putting the value of x and y one by one then we find out that those are satisfying the given expression.

8 0
4 years ago
What is the equation of this line in slope intercept form?
erica [24]

<u>answer:</u> d. y = 4/5 (i think you didn't put the x)

<u>explanation:</u> slope is rise over run. so, if you start a 0, which is the y-intercept, and go up 4 units and 5 units right. and do till' you hit the end of the graph.

then to start at 0 again, then go down 4 units and 5 units left, to make the slope of this line.

hope this helps! ❤from peachimin

4 0
3 years ago
Solve for y, give the slope and y intercept 5y=20, -y + 3=15x, y +1/3x=17
qaws [65]
     5y=20                                     Equation

y=4                                            Divide by 5 on both sides

5(4)=20                                     Plug in for y

20=20                                        Simplify

y=4
slope= 0
y-intercept= 4

     ^{-}y+3=15x                           Equation

^{-}y=15x-3                              Subtract 3 from both sides

y=-15x+3                                  Divide both sides by -1 

- (^{-}15x+3) +3=15x               Plug in for y

15x-3+3=15x                            Distribute -1 into the parenthesis

15x=15x                                    Further simplified

y= -15x+3
slope= -15
y-intercept= 3

     y+ \frac{1}{3}x=17              Equation

y=^{-}\frac{1}{3}x+17               Subtract 1/3x from both sides

(^{-}\frac{1}{3}x+17 )+\frac{1}{3}x =17    plug in for y

17=17                                       Simplify

y= -1/3x+17
slope= -1/3
intercept= 17


8 0
3 years ago
Tan(y)+ cot(y)/csc(y)= sec(y) prove identity
ArbitrLikvidat [17]

[tan(y) + cot (y)]/csc (y)

tan (y) = sin (y)/cos (y)
cot (y) = cos (y)/sin (y)
csc (y) = 1/sin (y).
Now rewrite the expression with the equivalent values

[sin (y)/cos (y) + cos (y)/sin (y) ] / [1/sin (y)]

1st, let's work the Numerator only = [sin (y)/cos (y) + cos (y)].
                  = [(cos² (y) + sin² (y)]/ [cos (y).sin(y)]

or (cos² (y) + sin² (y) = 1, →Numerator = 1/[cos (y).sin(y)]

Denominator = csc (y) = [1/sin (y)], Then:

N/D = 1/[cos (y).sin(y)] / [1/sin (y)] =  [1 x sin (y)]/ [cos (y).sin (y)] = 1/cos (y)

 Or 1/cos (y) = sec (y) Q.E.D 
4 0
4 years ago
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