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inn [45]
3 years ago
8

Who runs the race faster?

Mathematics
1 answer:
Troyanec [42]3 years ago
6 0

Answer:

Hector

Step-by-step explanation:

Hector is running 2.57, which is less/faster then 2.63

have a nice day :3

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Giving loads of points to anyone who can answer these questions or even just most of them correctly!!!
cestrela7 [59]

Answer:

below :)

Step-by-step explanation:

1) 12

2}3/2

3)224.64

4)2 quarters

5)w=50

6)m=6y+7

7)42/6=7 x=6

8 0
2 years ago
24. q + r t s, for q = 46, r = 19. s = 54​
Kaylis [27]

(24 \times 46 )+ (19 \times t \times 54) =

1104 + 1026t

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

8 0
3 years ago
At the U.S open tennis championship a statistician keeps track of every serve that a player hits during the tournament. The mean
GarryVolchara [31]

Answer:

Step-by-step explanation:

Both 115 and 145 mph are above the mean.  Draw a normal curve and mark these speeds.  115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.

We need to find the area under the standard normal curve between 115 and 145.  This is equivalent to the area under the standard normal curve between z = 1 and z = 3.

I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area:  normalcdf(1, 3) = 0.1573.

The area between z = 1 and z = 3 is 0.1573.  In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.

8 0
3 years ago
Find the slope of the line given two points:
vesna_86 [32]

Answer:

<h3>The answer is option C</h3>

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

m =  \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(8, 10) and (-7, 14)

The slope is

m =  \frac{14 - 10}{ - 7 - 8}  =  \frac{4}{ - 15}  =  -  \frac{4}{15}  \\

We have the final answer as

-  \frac{4}{15}  \\

Hope this helps you

4 0
3 years ago
If an airplane descends 15 feet every 1.45 seconds, how far would the airplane travel in three and a half minutes? The equation
NemiM [27]

\qquad\qquad\huge\underline{{\sf Answer}}

Here we go ~

The air plane descends 15 feels every 1.45 seconds, so it's unit rate is :

\qquad \sf  \dashrightarrow \:  \dfrac{15}{1.45} \:  \:  ft / sec

Now we have to calculate the descent in 3.5 minutes ~

\qquad \sf  \dashrightarrow \:  \dfrac{15}{1.45} \:  \:   \times 3.5 \times 60

\qquad \sf  \dashrightarrow \: 2172.41 \:  \: ft

So, the airplane descends 2172.41 feels in three and a half minutes ~

5 0
2 years ago
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