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Taya2010 [7]
2 years ago
14

What action should you take if you become aware that sensitive compartmented information has been compromised

Computers and Technology
1 answer:
irina [24]2 years ago
5 0

The sensitive compartmented information can not be compromised and in case found with the incident it must be reported to the security officer.

<h3>What is Sensitive Compartmented Information?</h3>

The sensitive compartmented information is given as the sensitive information to the United States gathered with the source of the intelligence and the analytical process.

The information has been sensitive and was considered not to be compromised. In case the information is found to be compromised, the security officer of the information must be contacted to check into the details.

Learn more about sensitive information, here:

brainly.com/question/25948574

#SPJ1

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2. Write these functions definitions:
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Answer:

Complete the code with the following code segment:

void add2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

   cin>>num1>>num2;

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}

void sub2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

   cin>>num1>>num2;

   cout<<num1-num2;

}

void mul2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

   cin>>num1>>num2;

   cout<<num1*num2;

}

void div2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

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Explanation:

The function added to this solution are:

  • add2Numbers
  • sub2Numbers
  • mul2Numbers
  • div2Numbers

Each of the functions

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  • prompt user for inputs
  • gets user inputs from the user

For add2Numbers() function:

This line adds the two integer numbers and prints the result

   cout<<num1+num2;

For sub2Numbers() function:

This line subtracts the two integer numbers and prints the result

   cout<<num1-num2;

For mul2Numbers() function:

This line multiplies the two integer numbers and prints the result

   cout<<num1*num2;

For div2Numbers() function:

This if condtion checks if the denominator is 0

if(num2==0){

If yes, the following is printed

cout<<"Division by 0 is invalid";

If otherwise, the division is calculated and the result is printed

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<em>See attachment for complete program</em>

Download cpp
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