Answer: provided in the explanation section
Explanation:
Given that:
Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise
now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.
So, from here we have that D(k) is given by the following recorance relation:
D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise
Algorithm:
Valid sentence (s,k)
D [1 : : : k] ∦ array of boolean variable.
for a ← 1 to m
do ;
d(0) ← false
for b ← 0 to a - j
for b ← 0 to a - j
do;
if D[b] ∧ DICT s([b + 1 : : : a])
d (a) ← True
(b). Algorithm Output
if D[k] = = True
stack = temp stack ∦stack is used to print the strings in order
c = k
while C > 0
stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c
P = W (p) - 1
output stack
= 0 =
cheers i hope this helps !!!
Answer:
"The employee pay rate is normal" is the correct answer for the above question.
Explanation:
- The above question code is written in the c++ language, in which there is one variable of bool type whose value is true.
- And this variable is also tested in the if-condition which gives the true and the if-body will be executed.
- Then the internal if-condition will give the false result because the value of the empsalary is not less than 45000. It is because the above statement "empsalary=45000" will assign the value 45000 on the empsalary variable.
- Then the else block will be executed which prints "the employee pay rate is normal".
restart.is done after the computer is passed through configuration
Answer:
<h3>
<em><u>C</u></em><em><u>.</u></em><em><u> </u></em><em><u> </u></em><em><u>City</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>state</u></em><em><u> </u></em><em><u>where</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>was</u></em><em><u> </u></em><em><u>published</u></em></h3>
Explanation:
<h3>#CarryOnLearning</h3>
