<span> 5×-(3+9)
Substitute 6 for x
5(6)-(3+9)
Add 9 to 3
5(6)-12
Multiply 5 by 6
30-12
Final Answer: 18</span>
What is asked here is that you isolate y so that the equation takes the form of y = ..., where ... will be something that contains a, b and c but not y. So how do we get there? By applying some standard permutations to equations like so:
aby - b = c
First, we bring the -b term to the right hand side by adding b left and right:
aby -b+b = c+b
The -b and +b cancel out, so we get:
aby = c + b
Then, we divide left and right hand side by ab:
aby/ab = (c+b)/ab
Again, the ab/ab on the left cancels out (it is 1), so we get:
y = (c+b)/ab
And we're done!
So you have to know that it is allowed to add or subtract something (anything) to/from the left and right hand side of an equation. Likewise, you have to know that it is allowed to multiply or divide by something, as long as it isn't 0.
Given that the two functions are
and 
We need to determine the value of 
<u>The value of </u>
<u>:</u>
The value of
can be determined using the formula,
![(f \circ g)(x)=f[g(x)]](https://tex.z-dn.net/?f=%28f%20%5Ccirc%20g%29%28x%29%3Df%5Bg%28x%29%5D)
Substituting
in the above formula, we get;
![(f \circ g)(x)=f[-9x^2-2x+1]](https://tex.z-dn.net/?f=%28f%20%5Ccirc%20g%29%28x%29%3Df%5B-9x%5E2-2x%2B1%5D)
Now, substituting
in the function
, we get;



Thus, the value of
is 
<u>The value of </u>
<u>:</u>
The value of
can be determined by substituting x = -6 in the function 
Thus, we have;




Thus, the value of
is -2797
Hence, Option B is the correct answer.
Answer:
The mean of this distribution is 36 years.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

There is a 0.02275 probability that the age of any randomly chosen person in the department is less than 22
This means that when X = 22, Z has a pvalue of 0.02275. So when X = 22, Z = -2. So





The mean of this distribution is 36 years.
You have 1 out of 5 chances to get a A in the spinner
<span>You have a 1 out of 6 chances to get a 4 </span>
<span>1/5 times (x) 1/6 = 1/30</span>