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V125BC [204]
3 years ago
6

If × = 6 what is 5×-(3+9)

Mathematics
2 answers:
Nadya [2.5K]3 years ago
5 0
The answer is 18 because 5x6 is 30 and 9+3=12 and 30-12 is 18
olga nikolaevna [1]3 years ago
4 0
<span> 5×-(3+9)
Substitute 6 for x
5(6)-(3+9)
Add 9 to 3
5(6)-12
Multiply 5 by 6
30-12
Final Answer: 18</span>
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Suppose a cheetah could travel 1.5 hours a top speed covering 111.9 miles how far could the cheetah travel in 1 hour
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Answer:

1 hour = 74.6

Step-by-step explanation:

111.9/ 3 = 37.3

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two trains leave stations 210 miles apart at the same time and travel tword each other. one train at 85 miles per hour while the
hodyreva [135]

recall your d = rt, distance = rate * time.


let's say we have two trains, A and B, A is going at 85 mph and B at 65 mph.


they are 210 miles apart and moving toward each other, at some point they will meet, when that happens, the faster train A has covered say d miles, and the slower B has covered then the slack from 210 and d, namely 210 - d.


When both trains meet, A has covered more miles than B because A is faster, however the time both have been moving, is the same, say t hours.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ \textit{Train A}&d&85&t\\ \textit{Train B}&210-d&65&t \end{array}\\\\ \dotfill\\\\ \begin{cases} \boxed{d}=85t\\ 210-d=65t\\[-0.5em] \hrulefill\\ 210-\boxed{85t}=65t \end{cases} \\\\\\ 210=150t\implies \cfrac{210}{150}=t\implies \cfrac{7}{5}=t\implies \stackrel{\textit{one hour and 24 minutes}}{1\frac{2}{5}=t}

3 0
3 years ago
2. At 1 pm, you leave Ellensburg at a constant speed of 75 miles per hour. At 2:30 pm, your
MA_775_DIABLO [31]

Here, we are required to determine how many hours your friend will drive in order to catch you.

(a)<em> Your friend will have to drive 7 and a half hours inorder to catch </em><em>you.</em>

<em>(</em><em>b)</em><em> </em><em>You </em><em>both </em><em>will </em><em>be </em><em>6</em><em>7</em><em>5</em><em> </em><em>miles</em> <em>away </em><em>from </em><em>Ellensburg</em><em> </em><em>at </em><em>that </em><em>time.</em>

If you leave at 1 pm; At 2:30pm;

  • That is; 1 and a half hours after leaving; you must have covered a distance, d = 75 × 1.5
  • d = 112.5miles.

Therefore, your position; S after 2:30pm is given by;

S(a) = 75t + 112.5 miles from Ellensburg.

For your friend; travelling at 90miles/hr;

  • His position is given as; S(b) = 90 × t

(a) For your friend to catch you, you both must be in the same position;

  • i.e S(a) = S(b)

75t + 112.5 = 90t

90t -75t = 112.5

t = 112.5/15

t = 7.5hours

(b) To determine how far you both are from Ellensburg; we can either evaluate:

S(b) = 90t or S(a) = 75t + 112.5

Therefore, By evaluating S(b) = 90t.

S(b) = 90 × 7.5

S(b) = 675miles from Ellensburg.

Read more:

brainly.com/question/24234606

6 0
2 years ago
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