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2 years ago

12.6-0.027=? Do the calculation on a page then add the pic to reply plss

Mathematics

1 answer:

valkas [14]2 years ago

7 0

See the attached picture for the calculation:

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The weights of items produced by a company are normally distributed with a mean of 4.5 ounces and a standard deviation of 0.3 ou

GalinKa [24]

Answer:

The right solution is:

(a) 0.8849

(b) 12.28%

(c) 4.9935

(d) 28004

Step-by-step explanation:

Given:

Mean,

= 4.5

Standard deviation,

= 0.3

(a)

P(x > 4.14)

As we know,

⇒ $z = \frac{4.14-4.5}{0.3}$

$=-1.20$

then,

⇒ $P(z>-1.20) = P(z$

$=0.8849$

(b)

P(4.8 < x < 5.04)

= $P(\frac{4.8-4.5}{0.3} < \frac{x-\mu}{\sigma} < \frac{5.04-4.5}{0.3} )$

= $P(1$

= $P(z$

= $0.9641 -0.8413$

= $0.1228$

or,

= $12.28$ (%)

(c)

P(x > x) = 0.05

z value will be,

= 1.645

⇒ $1.645 = \frac{x - 4.5}{0.3}$

$x = 4.9935$

(d)

P(x < 5.01)

⇒ $z = \frac{x- \mu}{\sigma}$

$=\frac{5.01-4.5}{0.3}$

$=1.7$

P(z < 1.70) = 0.9554

⇒ $n = \frac{27875}{0.9954}$

$=28004$

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3 years ago

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Answer:

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I believe it's 800

Step-by-step explanation:

so you would have to divide the whole number by the percentage (5%) and get the answer.

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3 years ago

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12.6-0.027=? Do the calculation on a page then add the pic to reply plss​

12.6-0.027=? Do the calculation on a page then add the pic to reply plss