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vivado [14]
3 years ago
10

Consider f(x) = 2x2 + 1 and g(x) = 3x − 6. Which statement about f + g is true?

Mathematics
1 answer:
disa [49]3 years ago
7 0

Given:

The two functions are:

f(x)=2x^2+1

g(x)=3x-6

To find:

The correct statement about the function f+g.

Solution:

We have,

f(x)=2x^2+1

g(x)=3x-6

Adding both functions, we get

f+g=f(x)+g(x)

f+g=2x^2+1+3x-6

f+g=2x^2+3x-5

It is a quadratic function. So, option A is incorrect and option B is correct.

The domain of f+g is all real numbers because it is defined for all real values of x. So, option C is incorrect.

The range of f+g cannot be the all real numbers because it has a minimum value of y as the leading coefficient is positive. So, option D is incorrect.

Therefore, the correct option is B.

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Find the zeros of the function. Enter the solutions from least to greatest . h(x) = (- 4x - 3)(x - 3) lesser x = greater
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Answer:

  -3/4, 3

Step-by-step explanation:

The zeros are the values of x that make h(x)=0. Those are the values of x that make the factors of h(x) be zero.

  -4x -3 = 0   ⇒   x = -3/4

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The zeros of the function are -3/4 and 3.

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3 years ago
<img src="https://tex.z-dn.net/?f=g%28x%29%20%3D%203x%20-%206" id="TexFormula1" title="g(x) = 3x - 6" alt="g(x) = 3x - 6" align=
VARVARA [1.3K]

Hey there! :)

Answer:

g^{-1} (g(10))=10

Step-by-step explanation:

Begin by calculating g(10):

g(x) = 3x - 6

Substitute in 10 for x:

g(10) = 3(10) - 6

g(10) = 30-6

g(10) = 24.

Plug '24' into 'x' into g^{-1} (x)

g^{-1} (24)=\frac{(24) + 6}{3}

Simplify:

g^{-1} (24)=\frac{30}{3}

g^{-1} (24)=10

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