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lidiya [134]
2 years ago
7

1. The Hg columns in Diagram A are of equal height. If the pressure of the confined gas is 749 mm Hg, what is the atmospheric pr

essure in mm Hg?​
Chemistry
1 answer:
Finger [1]2 years ago
4 0

We have that the Atmospheric pressure in mm Hg

P_{N_2}=0.78*749\\\\P_{N_2}=684.22mmHg

From the question we are told

The Hg columns in Diagram A are of equal height. If the pressure of the confined gas is 749 mm Hg, what is the atmospheric pressure in mm Hg

Generally the equation for the Moles Fraction of N   is mathematically given as

Mole N=\frac{mole of NO_2}{Miles of Mixture}\\\\Moles=\frac{n_{N_2}}{n_t}

Since Generally

Composition of N_2 in air is=\%78

n_{N_2}=78*N_a\\\\X_{N_2}=\frac{78}{100}\\\\\X_{N_2}=0.78

Therefore

Atmospheric pressure in mm Hg

P_{N_2}=0.78*749\\\\P_{N_2}=684.22mmHg

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An unknown amount of acid can often be determined by adding an excess of base and then back-titrating the excess. A 0.3471−g sam
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Explanation:

The given data is as follows.

       Mass of mixture = 0.3471 g

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Hence,   moles of NaOH in 97 ml = \frac{0.1090 \times 97}{1000}

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                  \frac{6.247 \times 10^{-3}}{3}

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                         = 83.293 \times 10^{-3} g

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Therefore,       40 g NaOH = 122 g benzoic acid

So,            0.0832 g NaOH = \frac{122 g}{40 g} \times 0.0832 g

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Thus, we can conclude that mass % of benzoic acid is 73.10%.

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3 years ago
On the basis of the Ksp values below, what is the order of the solubility from least soluble to most soluble for these compounds
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Answer:

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Explanation:

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Ksp = s² = 1.8 x 10⁻¹⁰  ∴ s = √ 1.8 x 10⁻¹⁰   = 1.3 x 10⁻⁵

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