Taking into account the reaction stoichiometry, 340.0 moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
CO₂ + 4 H₄ → CH₄ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- CO₂: 1 mole
- H₄: 4 moles
- CH₄: 1 mole
- H₂O: 2 moles
<h3>Moles of CH₄ formed</h3>
The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?
<u><em>moles of CH₄= 340.4 moles</em></u>
Then, 340.0 moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas
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Composting is a technique that allows biodegradable materials of urban, domestic and industrial origin to be degraded to form humus, a type of soil that is very fertile and extremely rich in micronutrients.
These biodegradable materials are materials of organic origin, such as food scraps, fruit peels, pieces of vegetables, among others. As the domestic environment generates a large amount of organic waste, composting in this environment is very favorable, and it can generate a very rich soil to be used in the garden, in vegetables, among other places.
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Answer:
a. atoms are indivisible. ... atoms can not be destroyed in chemical reactions.
Explanation:
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The molecular formula :
C₆H₁₄O₃PF
<h3>Further explanation</h3>
Given
39.10% carbon, 7.67% hydrogen, 26.11% oxygen, 16.82% phosphorus, and 10.30% fluorine.
Required
The molecular formula
Solution
mol ratio :
C = 39.1 : 12 = 3.258
H = 7.67 : 1 = 7.67
O = 26.11 : 16 = 1.632
P = 16.82 : 31 = 0.543
F = 10.3 : 19 = 0.542
Divide by 0.542
C = 6
H : 14
O = 3
P = 1
F = 1
The empirical formula :
C₆H₁₄O₃PF
(The empirical formula)n = the molecular formula
(C₆H₁₄O₃PF)=184.1
(6.12+14.1+3.16+31+19)n=184.1
(184)n=184.1
n = 1
5.00 moles of a binary, group 2 oxide are found to have a mass of 521 g. The group 2 metal is Strontium.
According to question 5 moles of binary group 2 metal oxide mass =521 g
So, 1-mole metal oxide mass will be =521 / 5=104.2 g
Now, as metal oxide is group 2 oxide so metal: oxygen =1: 1
So the mass of metal is =104.2-16=88.2 gm (as the atomic mass of oxygen is 16 g
Therefore, the metal is Strontium(Sr) whose atomic mass is 87.62 g which is nearly 88.2 gm
So, the formula of metal oxide is SrO
The group two metal here is Sr which is strontium and lies in the same group as calcium.
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