I got this idk if it's correct: For measuring large distances, the kilometer (103 or 1000 meters) is often used. The basic unit of volume in the metric system is the liter (l). The most common derived unit is the milliliter (ml) (10-3 or 1/1000 of a liter). The volume of a milliliter is equal to the volume of a cube 1 centimeter per side.

5 0

3 years ago

a student reacted 40 drops of an unknown amine with 20 drops of iodomethane in 2 ml of a suitable solvent mixture. after 15 minu

lutik1710 [3]

The compound formed is the quaternary ammonium salt N,N,N-trimethyl-1-phenylmethanaminium iodide.

Quaternary ammonium salts are formed when methyl iodide reacts with an amine. The quaternary ammonium salt is an ionic substance which often has a high melting point. Remember that the melting point of a substance can be used to identify the substance.

In this case, a student reacted 40 drops of an unknown amine with 20 drops of iodomethane in 2 ml of a suitable solvent mixture. after 15 minutes of reaction, a white precipitate formed. the precipitate was isolated and its melting point was recorded to be 178 °c. This precipitate must be N,N,N-trimethyl-1-phenylmethanaminium iodide (Benzyltrimethylammonium iodide) because it is a quaternary ammonium salt whose melting point is 178 °c.

Learn more: brainly.com/question/5325004

8 0

2 years ago

Determine the amount of energy (heat) in joules required to raise the temperature of 20g of gold from 5°C to 37°C.

insens350 [35]

Answer:

The answer to your question is E = 83.2 J

Explanation:

Data

Element: Gold

Initial temperature = T1 = 5°C

Final temperature = T2 = 37°C

mass = 20 g

Specific heat = 130 J/kg°K

Process

1.- Convert temperature to kelvin

T1 = 273 + 5 = 278°K

T2 = 273 + 37 = 310°K

2.- Convert mass to kg

1000 g --------------- 1 kg

20 g --------------- x

x = (20 x 1)/1000

x = 0.02 kg

3.- Formula

E = mC(T2 -T1)

4.- Substitution

E = (0.02)(130)(310 - 278)

E = (0.02)(130)(32)

E = 83.2 J

3 0

3 years ago