Answer:
Naphthalene has C2-rotational axis passing through the C9-C10 bond. It has two C2-axes perpendicular to the principal C2-rotational axis (one is passing through the mid-point of the C9-C10 bond another passing through the midpoints of C2-C3, C9-C10, C6-C7 bonds).
Explanation:
D. The Moon is the Earth's largest natural satellite.
There you go!
Let's
assume that the gas in the balloon is an ideal gas.
We can use
combined gas law,
PV/T =
k (constant)
Where, P is
the pressure of the gas, V is volume of the gas and T is the temperature of the
gas in Kelvin.
For two
situations, we can use that as,
P₁V₁/T₁= P₂V₂/T₂
P₁
= 2.95 atm
V₁
= 7.456 L
T₁ = 379 K
P₂ = ?
V₂
= 4.782 L
T₂ = 212 K
By applying
the formula,
2.95 atm x 7.456 L / 379 K = P₂ x 4.782 L / 212 K
P₂
= (2.95 atm x 7.456 L x 212 K) / (379 K x 4.782 L)
P₂
= 2.57 atm
Hence, the answer is 2.57 atm.
Answer: Use c1(v1) = c2(v2) to solve<span> that </span>problem. 87%(200) = (35.5<span>%)v2 v2 ≈ 490.5. I hope this helps! Source(s)</span>
The mas of the products are given below:
- mass of oxygen produced = 0.7056 g of oxygen
- mass of water produced = 0.794 g of hydrogen
<h3>How many moles are there in 5 ml of 30% of hydrogen peroxide?</h3>
The moles of hydrogen peroxide in 5 ml of 30% of hydrogen peroxide is calculated using the formula:
Moles = concentration * volume
Molarity of 30% of hydrogen peroxide = 8.82 mol/L
Moles = 8.82 * 5/1000 = 0.0441 moles
The equation of the the decomposition of hydrogen peroxide is given as:
2 H₂O₂ -----> 2 H₂O + O₂
Based on the mole ratio;
mass of oxygen produced = 0.0441/2 * 32 g = 0.7056 g of oxygen
mass of water produced = 0.0441 * 18 g = 0.794 g of hydrogen
Therefore, the mass of the products of the decomposition of hydrogen peroxide is determined from the mole ratio of the reaction.
Learn more about mole ratio at: brainly.com/question/19099163
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