The half-life of a certain radioactive material is 36 days. An initial amount of the material has a mass of 487kg. Write an expo
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Answer:
Value of expression 1 = 3
Value of expression 2 = 42
Value of expression 3 = 15
Value of expression 4 = 2
Step-by-step explanation:
Expression 1 : the sum of m and 3 divided by the difference of m minus 3
Expression 1
Substitute m = 6
So, value of expression 1=
Expression 2 : the sum of 3 times m and 4 times m
Expression 2: 3m+4m
Substitute m = 6
So, value of expression 2=3m+4m=3(6)+4(6)=42
Expression 3 : the difference of the product of 3 and m minus the quotient of m divided by 2
Expression 3:
Substitute m = 6
So, value of expression 2=
Expression 4 :the quotient of 6 divided by the difference of m minus 3
Expression 4:
Substitute m = 6
So, value of expression 4=