Answer:
9.577 mm.
Step-by-step explanation:
We have been given that the diameter of a quarter is 24.26 mm and the diameter of a nickel is 21.21 mm.
Let us find the circumference of quarter and nickel using circumference of circle formula.
, where r represents radius of the circle.
Since we know that diameter of circle is 2 times its radius, so let us find radius of quarter and nickel by dividing their diameter by 2.
Therefore, circumference of quarter is 76.1764 mm.
Let us find circumference of nickel.
Let us subtract circumference of nickel from circumference of quarter.
Therefore, the distance around a quarter is 9.577 millimeters bigger than a nickel.
Answer:
D
Step-by-step explanation:
without knowing anything about the background of the function and what it is used for, I give it the max. possible domain (the set or interval of all possible input values).
and so,
Defined for all m >= 0 and n >= 0.
there is no information provided that would eliminate m = 0 or n = 0.
A'(-9,4)
B'(-4,4)
C'(0,-4)
D'(-5,-4)
Since NS bisects QNR, the angles SNQ and SNR will be congruent.
They are congruent that means they are equal to each other. We will set them equal to each other and find the value of x first.
6x - 57 = 2x + 15
6x = 2x + 72
4x = 72
x = 18
Now we will substitute 18 for x in each angle measure and find measure of them.
Angle SNQ = 6(18) - 57 = 51
Angle SNR = 2(18) + 15 = 51
Now we will add both angles to find the total measure of angle QNR.
51 + 51 = QNR
102 = QNR
Hope this helps :)
