Let

where we assume |r| < 1. Multiplying on both sides by r gives

and subtracting this from
gives

As n → ∞, the exponential term will converge to 0, and the partial sums
will converge to

Now, we're given


We must have |r| < 1 since both sums converge, so


Solving for r by substitution, we have


Recalling the difference of squares identity, we have

We've already confirmed r ≠ 1, so we can simplify this to

It follows that

and so the sum we want is

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?
Answer:
(-1,4)(1,4)
2
Step-by-step explanation:
Answer:
Step-by-step explanation:
- sqrt(39) and square root 47
are the limits. The - square root of 39 is smaller than - 6. So the integer to use here is - 6
sqrt (47) = 6.686. Here the square root is larger than the closest integer.
The integer to use is 6
- 6 + 6 = 0
Answer:
f(3) =-12
f(-1) =-12
Step-by-step explanation:
HELLO THERE
f(3)=-2(3)^2+8(3)
f(3)=-36+24
f(3)=-12
----------------------------
f(-1) =2(-1) ^2+8(-1)
f(-1) =-4-8
f(-1) =-12
//Both equal -12//
HAVE A GREAT DAY